How to check if NSMutableArray object contains NaN

Question

I have an NSMutableArray with 1 float value and 4 nan values. I want to execute some operations if the array object is nan. How can I write an if condition?

do you want to check that whether array contains any object or not!!!???? — NiravPatel, Oct 07 '13 at 11:08

BaSha · Accepted Answer · 2013-10-07T11:23:41.000

4

try isnan function

Iterate your array and put check

isnan([[Array objectAtIndex:i] floatValue])

(dont forget to add math.h library)

edited Oct 07 '13 at 11:23

answered Oct 07 '13 at 11:09

BaSha

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Right, let me correct it – BaSha Oct 07 '13 at 11:22
isnan([[array objectAtIndex:i] floatValue]) worked like a charm! without math.h import. – Ali Sufyan Oct 07 '13 at 11:27

score 1 · Answer 2 · answered Oct 07 '13 at 11:12

1

NSNumber *num = //your number;
float value = [num floatValue];
if (isnan(value))
{
    NSLog(@"is nan");
}

answered Oct 07 '13 at 11:12

Inder Kumar Rathore

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score 1 · Answer 3 · answered Oct 07 '13 at 11:20

Do something like this:

NSMutableArray *array = [[NSMutableArray alloc] init];
[array addObject:[NSNumber numberWithFloat:1.0]];
[array addObject:[NSNull null]];
[array addObject:[NSNull null]];
[array addObject:[NSDecimalNumber notANumber]];


BOOL foundNull = NO;
for (id value in array) {
    if (!value || value == [NSNull null]) {
        foundNull = YES;
    } else if ([value isKindOfClass:[NSDecimalNumber class]]) {
        if ([value isEqualToNumber:[NSDecimalNumber notANumber]]) {
            foundNull = YES;
        }
    }
}

NSLog(@"Found null/NaN: %i", foundNull);

score 0 · Answer 4 · answered Oct 07 '13 at 11:29

0

You can also use

[NSDecimalNumber notANumber] method to compare and check if this a valid number or not.

answered Oct 07 '13 at 11:29

RK-

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How to check if NSMutableArray object contains NaN

4 Answers4