How to convert AM/PM timestmap into 24hs format in Python?

Question

I'm trying to convert times from 12 hour times into 24 hour times...

Automatic Example times:

06:35  ## Morning
11:35  ## Morning (If m2 is anywhere between 10:00 and 12:00 (morning to mid-day) during the times of 10:00 and 13:00 (1pm) then the m2 time is a morning time)
1:35  ## Afternoon
11:35  ## Afternoon

Example code:

m2 = "1:35" ## This is in the afternoon.
m2 = datetime.strptime(m2, "%H:%M")
print m2

Expected Output:

13:35

Actual Output:

1900-01-01 01:35:00

I tried a second variation but again didn't help :/

m2 = "1:35" ## This is in the afternoon.
m2split = m2.split(":")
if len(m2split[0]) == 1:
    m2 = ("""%s%s%s%s""" % ("0", m2split[0], ":", m2split[1]))
    print m2
m2temp = datetime.strptime(m2, "%I:%M")
m2 = m2temp.strftime("%H:%M")

What am I doing wrong and how can I fix this?

http://stackoverflow.com/questions/13855111/convert-24-hours-time-to-12-hours-in-python — The Humble Rat, Oct 07 '13 at 15:54
There is nothing in the string `"1:35"` to indicate that it is an afternoon time, so `strptime()` will assume it is morning. To indicate afternoon, you'd need an am/pm indicator of some sort. — Jonathan Leffler, Oct 07 '13 at 15:54
[SO 13855111](http://stackoverflow.com/q/13855111) is mainly about the converse problem, converting 24 hour to 12 hour time. — Jonathan Leffler, Oct 07 '13 at 15:55
@JonathanLeffler The problem is I can't automatically add the PM to the string time? If the m2 value is 10:00 to 12:00 and the real life time is 10:00 to 13:00 (morning to 1pm) then m2 should be considered a morning time, everything else should be considered an afternoon time. — Ryflex, Oct 07 '13 at 16:21
If you have rules for deciding whether a time is AM or PM, you need to write them in code. Python can't read your mind. — dan04, Oct 07 '13 at 16:31
@dan04 I just made the said rules to get around this problem... — Ryflex, Oct 07 '13 at 16:33

score 47 · Answer 1 · answered Feb 21 '16 at 19:51

This approach uses strptime and strftime with format directives as per https://docs.python.org/2/library/datetime.html#strftime-strptime-behavior, %H is the 24 hour clock, %I is the 12 hour clock and when using the 12 hour clock, %p qualifies if it is AM or PM.

    >>> from datetime import datetime
    >>> m2 = '1:35 PM'
    >>> in_time = datetime.strptime(m2, "%I:%M %p")
    >>> out_time = datetime.strftime(in_time, "%H:%M")
    >>> print(out_time)
    13:35

score 33 · Answer 2 · answered Oct 07 '13 at 15:57

33

You need to specify that you mean PM instead of AM.

>>> from datetime import *
>>> m2 = '1:35 PM'
>>> m2 = datetime.strptime(m2, '%I:%M %p')
>>> print(m2)
1900-01-01 13:35:00

answered Oct 07 '13 at 15:57

dan04

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2

Plus, he needs `strftime` to get his desired output. – Robᵩ Oct 07 '13 at 15:59
@dan04 my strings (m2) are automatically generated elsewhere, I can't add "PM" onto them. I've edited my original post to show some of my times.. – Ryflex Oct 07 '13 at 16:13
This should be the answer, indeed. Other answers are clones and some others, achieve the result, but using extra computations and resources, unnecessary in comparison to what this proposal is offering. – ivanleoncz Jun 27 '22 at 17:15

score 7 · Accepted Answer · answered Oct 07 '13 at 17:59

7

Try this :)

Code:

currenttime = datetime.datetime.now().time().strftime("%H:%M")
if currenttime >= "10:00" and currenttime <= "13:00":
    if m2 >= "10:00" and m2 >= "12:00":
        m2 = ("""%s%s""" % (m2, " AM"))
    else:
        m2 = ("""%s%s""" % (m2, " PM"))
else:
    m2 = ("""%s%s""" % (m2, " PM"))
m2 = datetime.datetime.strptime(m2, '%I:%M %p')
m2 = m2.strftime("%H:%M %p")
m2 = m2[:-3]
print m2

Output:

13:35

answered Oct 07 '13 at 17:59

SMNALLY

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I know this is an old answer, but why are your format strings triple quoted? Also `m2` is a string already, you could just write `m2 += " AM"`. Also you're doing string comparisons in `m2 >= "10:00"`. Why is this answer accepted... – Enrico Borba Jul 11 '18 at 00:21

score 5 · Answer 4 · answered Nov 27 '17 at 07:16

5

If date is in this format (HH:MM:SSPM/AM) the following code is effective :

a=''
def timeConversion(s):
   if s[-2:] == "AM" :
      if s[:2] == '12':
          a = str('00' + s[2:8])
      else:
          a = s[:-2]
   else:
      if s[:2] == '12':
          a = s[:-2]
      else:
          a = str(int(s[:2]) + 12) + s[2:8]
   return a


s = '11:05:45AM'
result = timeConversion(s)
print(result)

answered Nov 27 '17 at 07:16

Vikas Periyadath

3,088
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Elegant as an actual algorithm not using much of built-in functions. – Fahad Aug 02 '19 at 13:05
elegant! beautiful! – zx1986 Jun 14 '22 at 05:44

score 4 · Answer 5 · answered Apr 28 '16 at 17:56

time = raw_input().strip() # input format in hh:mm:ssAM/PM
t_splt = time.split(':')
if t_splt[2][2:] == 'PM' and t_splt[0] != '12':
    t_splt[0] = str(12+ int(t_splt[0]))
elif int(t_splt[0])==12 and t_splt[2][2:] == 'AM':
    t_splt[0] = '00'
t_splt[2] = t_splt[2][:2]
print ':'.join(t_splt)

score 2 · Answer 6 · answered Jul 28 '17 at 17:35

Try this

dicti = 
{'01':13,'02':14,'03':15,'04':16,'05':17,'06':18,'07':19,'08':20,'09':21,'10':22,'11':23,'12':12}
s = '12:40:22PM'
if s.endswith('AM'):
if s.startswith('12'):
    s1=s[:8]
    bb=s1.replace('12','00')
    print bb
else:
    s1=s[:8]
    print s1
else:
s1=s[:8]
time= str(s[:2])
ora=str(dicti[time])
aa=s1.replace(time,ora)
print aa

score 2 · Answer 7 · answered Jul 08 '20 at 13:29

2

def timeConversion(s):
    if "PM" in s:
        s=s.replace("PM"," ")
        t= s.split(":")
        if t[0] != '12':
            t[0]=str(int(t[0])+12)
            s= (":").join(t)
        return s
    else:
        s = s.replace("AM"," ")
        t= s.split(":")
        if t[0] == '12':
            t[0]='00'
            s= (":").join(t)
        return s

answered Jul 08 '20 at 13:29

jugesh

70
6

2

This is literally the easiest approach. Good one! – Raghav Gupta Nov 04 '20 at 14:09

score 1 · Answer 8 · answered Dec 13 '18 at 10:20

1

One more way to do this cleanly

def format_to_24hr(twelve_hour_time): return datetime.strftime( datetime.strptime( twelve_hour_time, '%Y-%m-%d %I:%M:%S %p' ), "%Y-%m-%d %H:%M:%S")

answered Dec 13 '18 at 10:20

Alok Kumar Singh

2,331
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score 0 · Answer 9 · answered Apr 14 '20 at 07:21

0

Instead of using "H" for hour indication use "I" as described in the example bellow:

from datetime import *
m2 = 'Dec 14 2018 1:07PM'
m2 = datetime.strptime(m2, '%b %d %Y %I:%M%p')
print(m2)

Please check this link

answered Apr 14 '20 at 07:21

Oldemiro Henry Williams Baloi

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1
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Ishaan · Answer 10 · 2020-11-18T02:47:58.200

To convert 12 hour time format into 24 hour time format

''' To check whether time is 'AM' or 'PM' and whether it starts with 12 (noon or morning). In case time is after 12 noon then we add
12 to it, else we let it remain as such. In case time is 12 something in the morning, we convert 12 to (00) '''

def timeConversion(s):

    if s[-2:] == 'PM' and s[:2] != '12':
        time = s.strip('PM')
        conv_time = str(int(time[:2])+12)+time[2:]

    elif s[-2:] == 'PM' and s[:2] == '12':
        conv_time = s.strip('PM')

    elif s[-2:] == 'AM' and s[:2] == '12':
        time = s.strip('AM')
        conv_time = '0'+str(int(time[:2])-12)+time[2:]

    else:
        conv_time = s.strip('AM')
        
    return conv_time

It would be helpful is you had a minimum of explanation of what your solution does. — Serge de Gosson de Varennes, Nov 16 '20 at 14:30

score 0 · Answer 11 · answered Dec 17 '20 at 13:31

0

the most basic way is:

t_from_str_12h = datetime.datetime.strptime(s, "%I:%M:%S%p")
str_24h =  t_from_str.strftime("%H:%M:%S")

answered Dec 17 '20 at 13:31

AgE

387
2
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Piotr Rembelski · Answer 12 · 2021-01-10T15:35:27.140

0

#format HH:MM PM
def convert_to_24_h(hour):
    if "AM" in hour:
        if "12" in hour[:2]:
            return "00" + hour[2:-2]
        return hour[:-2]
    elif "PM" in hour:
        if "12" in hour[:2]:
            return hour[:-2]
    return str(int(hour[:2]) + 12) + hour[2:5]

edited Jan 10 '21 at 15:35

answered Jan 08 '21 at 15:25

Piotr Rembelski

1
1

Use 4 spaces per indentation level. See [PEP 8 -- Style Guide for Python Code](https://www.python.org/dev/peps/pep-0008/#indentation) – AcK Jan 08 '21 at 16:56

score 0 · Answer 13 · answered Dec 23 '21 at 05:56

Since most of the manual calculation seems a bit complicated, I am sharing my way of doing it.

# Assumption: Time format (hh:mm am/pm) - You can add seconds as well if you need
def to_24hr(time_in_12hr):
    hr_min, am_pm = time_in_12hr.lower().split()
    hrs, mins = [int(i) for i in hr_min.split(":")]
    hrs %= 12
    hrs += 12 if am_pm == 'pm' else 0
    return f"{hrs}:{mins}"

print(to_24hr('12:00 AM'))

score 0 · Answer 14 · answered Jul 02 '22 at 09:57

# 12-hour to 24-hour time format
import re

s = '12:05:45PM'


def timeConversion(s):
    hour = s.split(':')
    lastString = re.split('(\d+)', hour[2])
    if len(hour[2]) > 2:
        hour[2] = lastString[1]
    if 'AM' not in hour or 'am' not in hour or int(hour[0]) < 12:
        if (lastString.__contains__('PM') and int(hour[0]) < 12) or (lastString.__contains__('pm') and int(hour[0]) < 12):
            hour[0] = str(int(hour[0]) + 12)
    if hour[0] == '12' and (lastString.__contains__('AM') or lastString.count('am')):
        hour[0] = '00'
    x = "{d}:{m}:{y}".format(d=hour[0], m=hour[1], y=hour[2])
    return x


print(timeConversion(s))

score 0 · Answer 15 · answered Sep 13 '22 at 04:47

Here's my solution by using python builtin functions to convert 12-hour time format into 24-hour time format

def time_conversion(s):
    if s.endswith('AM') and s.startswith('12'):
        s = s.replace('12', '00')
    if s.endswith('PM') and not s.startswith('12'):
        time_s = s.split(':')
        time_s[0] = str(int(time_s[0]) + 12)
        s = ":".join(time_s)
        
    s = s.replace('AM', '').replace('PM', '')
    
    return s

time_conversion('07:05:45PM') 

19:05:45

I would reccomand time_s[0] = '%02d'%(int(time_s[0]) + 12) – 00__00__00 Jan 24 '23 at 10:50 — 00__00__00, Jan 24 '23 at 10:50

score -1 · Answer 16 · edited Apr 06 '18 at 18:02

-1

%H Hour (24-hour clock) as a zero-padded decimal number.
%I Hour (12-hour clock) as a zero-padded decimal number.

m2 = "1:35" ## This is in the afternoon.
m2 = datetime.strptime(m2, "<b>%I</b>:%M")
print(m2)

edited Apr 06 '18 at 18:02

Skandix

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answered Apr 06 '18 at 17:18

szerem

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%H Hour (24-hour clock) as a zero-padded decimal number.
%I Hour (12-hour clock) as a zero-padded decimal number. m2 = "1:35" ## This is in the afternoon. m2 = datetime.strptime(m2, "%I:%M") print(m2) – szerem Apr 06 '18 at 17:19
While this code snippet may solve the question, [including an explanation](https://meta.stackexchange.com/questions/114762/explaining-entirely-code-based-answers) helps to improve the quality of your response. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. – Stefan Crain Apr 06 '18 at 17:52