How to include uneditable information on a form's display?

Question

I am using a django formset containing forms that specify user friendship preferences.

My form fields are:

    siteuser_id = forms.IntegerField(widget=forms.HiddenInput())
    subscribed = forms.BooleanField(required=False)
    ally = forms.BooleanField(required=False)
    enemy = forms.BooleanField(required=False)

The goal is to display all of a person's friends and that person's status within the game.

When I display the forms in the formset, I'd like to display the nickname (nicknames are not unique or I would just use it instead of siteuser_id) of the person alongside the friendship preference for that person.

I tried making username a form field, but that makes it editable, and I just want it to display within the table, not be editable.

Help?

Hi Marcin, I don't want a form field. I just want the information to display. — Foo Party, Oct 08 '13 at 14:07

Aamir Rind · Answer 1 · 2013-10-07T22:23:40.837

1

Just add the readonly attribute to the field:

username = forms.CharField(widget=forms.TextInput(attrs={"readonly": "readonly"}))

Makes the field non-editable.

edited Oct 07 '13 at 22:23

answered Oct 07 '13 at 22:12

Aamir Rind

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Hm. That still makes a text box though. I think it's kind of ugly to have a non-editable text box. – Foo Party Oct 08 '13 at 13:58

score 1 · Answer 2 · answered Oct 07 '13 at 22:24

1

In case you are using model formsets (or using them is an option) you can access the instance attribute of the form within the template.

For example:

{% for form in formset %}
    {{ form.instance.nickname }}
    {{ form }}
{% endfor %}

answered Oct 07 '13 at 22:24

ptrck

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score 1 · Accepted Answer · answered Oct 08 '13 at 14:41

1

It sounds like you don't necessarily want a form - you could just pass the data in objects to your template.

However, if you do want to do this with a form, you could set a custom widget for the form field, and subclass Widget. See https://docs.djangoproject.com/en/dev/ref/forms/widgets/.

answered Oct 08 '13 at 14:41

Marcin

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I think that will work. I've never made one. I'll give it a try. – Foo Party Oct 08 '13 at 14:51
I would have just put the information in the template, except it changes for each form in the formset and I have no way of knowing which form I'm on. – Foo Party Oct 08 '13 at 14:51
@FooParty No, you wouldn't "put the information in the template". You would pass the information to the template, and the template would render it. – Marcin Oct 08 '13 at 15:05
OK I made a custom widget and it works! – Foo Party Oct 08 '13 at 16:10
@FooParty Great! Feel free to accept and vote up this answer. – Marcin Oct 08 '13 at 16:10
OK. I also posted the code for my widget in case anyone needs it. – Foo Party Oct 08 '13 at 16:15

score 1 · Answer 4 · answered Oct 08 '13 at 16:14

Here is the custom widget I made to do this!

Just put this in a widgets.py file in your project:

from django.forms.widgets import Widget

class DisplayOnlyField(Widget):

    def __init__(self,attrs=None):
        self.attrs = attrs or {}
        self.required = False

    def render(self, name, value="", attrs=None):
        try:
            val = value
        except AttributeError:
            val = ""
        return val

Then in your views.py, put:

from projname.widgets import DisplayOnlyField

And on the field, it would be:

user_name = forms.CharField(widget=DisplayOnlyField())

How to include uneditable information on a form's display?

4 Answers4