what is the use keyword in php symfony

Question

I am new to PHP. I am trying to read the code in Symfony 2 app, and I am not able to understand what is this function.

Can anyone please explain to me what this function is doing. I am not able to get how is this variable defined

$def = function($name, $class, $args=[]) use ($container){
   return $container->doStuff($name, $class);
};

What is use doing there?

in simple words `use` makes `$container` variable available inside the anonymous function. — bansi, Oct 08 '13 at 04:09
is this syntax of `use` from php or symfony. i havent seen `use` word after function declarartion — user191542, Oct 08 '13 at 04:11

score 0 · Answer 1 · answered Oct 08 '13 at 04:11

Use keyword used in this way

<?php
namespace foo;
use My\Full\Classname as Another;

// this is the same as use My\Full\NSname as NSname
use My\Full\NSname;

// importing a global class
use ArrayObject;

$obj = new namespace\Another; // instantiates object of class foo\Another
$obj = new Another; // instantiates object of class My\Full\Classname
NSname\subns\func(); // calls function My\Full\NSname\subns\func
$a = new ArrayObject(array(1)); // instantiates object of class ArrayObject
// without the "use ArrayObject" we would instantiate an object of class foo\ArrayObject
?>

score 0 · Accepted Answer · answered Oct 08 '13 at 04:17

0

This:

$def=function($name, $class, $args=[]) use ($container){
   return $container->doStuff($name, $class);
};

is roughly the same than:

$def = my_function($container, $name, $class);

function my_function($container, $name, $class, $args=[]) {
  return $container->doStuff($name, $class);
}

answered Oct 08 '13 at 04:17

François Constant

5,531
1
33
39

thanks , i was going to ask that in comment that it means passing another parameter as arguments – user191542 Oct 08 '13 at 04:20

what is the use keyword in php symfony

2 Answers2