Rounding decimals to two decimal places in c#

Question

I want to round 54.5345 to 54.54 that is if I have a third decimal place then i want to add 1 to the 2nd decimal place.

I have tried using math.round but it always rounds down if the third decimal is less than 5

http://stackoverflow.com/questions/13482159/how-to-round-up-or-down-in-c — caleb.breckon, Oct 09 '13 at 21:59
Please read the concept of rounding on wikipedia [here](http://en.wikipedia.org/wiki/Rounding) — Tinwor, Oct 09 '13 at 22:00
seriously .! I know how rounding works but I want to round up 54.5345 to 54.54 and not 54.53 — Sabareesh Kkanan, Oct 09 '13 at 22:03
What do you want to have happen if the number is negative? Does `-54.5345` get *less negative* and therefore *larger*, and go to `-54.53` or do you want its *absolute value* to get larger and go to `-54.54` ? — Eric Lippert, Oct 09 '13 at 22:34

score 4 · Accepted Answer · answered Oct 09 '13 at 22:02

4

try:

d = Math.Ceiling(d * 100) / 100;

where d is your decimal.

answered Oct 09 '13 at 22:02

borkovski

What if the number is negative? – Eric Lippert Oct 09 '13 at 22:32
For my purpose its always going to Positive – Sabareesh Kkanan Oct 10 '13 at 14:04

score 0 · Answer 2 · edited May 23 '17 at 12:22

0

I think you should try this:

      double a = Math.Round(-57.5345, 2);

This works for negative numbers too.

The way you are rounding off is not correct.

You can also refer:

edited May 23 '17 at 12:22

Community

answered Oct 09 '13 at 23:08

Dev

Possible duplication of http://stackoverflow.com/questions/15643280/rounding-bigdecimal-to-always-have-two-decimal-places?rq=1 – Dev Oct 09 '13 at 23:17
please read the question again, I want to always round up the 2nd decimal if third decimal place exist – Sabareesh Kkanan Oct 10 '13 at 14:06

2 Answers2