IndexError: list index out of range Python Argument Input

Question

import sys
#print sys.argv[1]
def IndexSearchString():


    This function search a string in a file through index and gives the result.



    #fieldindex = int(sys.argv[1])-1
    stringsrch = sys.argv[2]
    #size = len(sys.argv)
    file_name = open("passwd", "r")
    #print "No of Argu ", size
    ''' 
    if sys.argv[1] == Null:
        print "Please enter argument"   
    '''
    if sys.argv[1].isdigit():
        fieldindex = int(sys.argv[1])-1
    else:
        print "Enter integer in 1st Argument"
        sys.exit(1)
    fieldindex = int(sys.argv[1])-1

    stringsrch = sys.argv[2]

    if len(sys.argv) > 3 :
        print "Enter two arguments only"
        sys.exit(1)

    for store_file in file_name:
        temp = store_file.split(":")
        search = temp[fieldindex]
        #print search 

        if stringsrch in search:
            print store_file

IndexSearchString()
    '''
    My Question is:
    I am taking two argument in the command line. Now I want to handle when only one     argument is given and also when no argument is given.
    Help me out 

    Error:
    Command Window Input: python SearchString.py 1 
    Traceback (most recent call last):
    File "SearchString.py", line 46, in <module>
    IndexSearchString() 
    File "SearchString.py", line 36, in IndexSearchString
    stringsrch = sys.argv[2]
    IndexError: list index out of range
    '''

Python has clearly modules like "argparse" for doing commandline options handling _properly_ - at least much better than your code. — , Oct 10 '13 at 06:59
when i take no argument i want that to be handled without try except — user2865801, Oct 10 '13 at 07:03
i am not giving search string, and its is giving me error and i want that to be handled — user2865801, Oct 10 '13 at 07:04
How are you calling this program. Ie what are typing on the command line? — Kevin, Oct 10 '13 at 14:43

score 0 · Answer 1 · answered Oct 10 '13 at 07:04

0

this

stringsrch = sys.argv[2]

should probably be this

stringsrch = sys.argv[1]

because no other place do you use

sys.argv[2]

answered Oct 10 '13 at 07:04

mjz19910

244
1
13

but already i am using sys.argv[1] for indexing – user2865801 Oct 10 '13 at 07:07
because of line 6 and 20 you would have to give the program two arguments you only gave it one – mjz19910 Oct 10 '13 at 08:01
`if len(sys.argv) < 2 : print "Enter two arguments" sys.exit(1)` you should also add this before you do anything in your script – mjz19910 Oct 10 '13 at 08:06

score 0 · Answer 2 · edited Dec 14 '15 at 00:17

0

in your Opinion: you should start with 0 in sys.argv

edited Dec 14 '15 at 00:17

Josh Crozier

233,099
56
391
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answered Oct 10 '13 at 07:07

micheal.yxd

118
1
7

where should i change that in my code ? – user2865801 Oct 10 '13 at 07:08
it would be great if u help me out – user2865801 Oct 10 '13 at 07:12
if you think you need second parameter, you uses `sys.argv[1]` – micheal.yxd Oct 11 '13 at 05:14

score 0 · Accepted Answer · edited May 23 '17 at 11:52

0

check this question out and see if it can help
python and sys.argv
add this after your "def..."

if len(sys.argv) < 3 :
  print "Please enter two arguments"
  sys.exit(1)

and change your other one

if len(sys.argv) > 3 :
        print "Enter two arguments only"
        sys.exit(1)

to

if len(sys.argv) > 4 :
        print "Enter only two arguments after the program"
        sys.exit(1)

even easier

if len(sys.argv) >= 0 | len(sys.argv) < 3 :
  fieldindex = int(sys.argv[1])-1  
else:
  sys.exit("enter up to 2 args")

edited May 23 '17 at 11:52

Community

1
1

answered Oct 10 '13 at 08:12

mjz19910

244
1
13

adding this after def still shows the same error – user2865801 Oct 10 '13 at 08:30
by the way you dont need to define searchsrch twice – mjz19910 Oct 11 '13 at 00:53

score 0 · Answer 4 · answered Oct 10 '13 at 12:05

0

Do not re-invent the wheel, but use one of the existing python command line argument parsers:

docopt - (from PyPI, pip install docopt)
argparse - (it is in standard library)

answered Oct 10 '13 at 12:05

Kimvais

38,306
16
108
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IndexError: list index out of range Python Argument Input

4 Answers4