Invalid argument supplied for foreach() in 2

Question

When trying to execute this code am getting an error like this

Invalid argument supplied for foreach() in line number 2

My code is:

<?php
$contacts= $getcontact_access->GetContacts($oauth, $access_token, $access_token_secret, false, true,$emails_count);
foreach($contacts as $k => $a)
 {
  $final = end($contacts[$k]);
   foreach($final as $email)
    {
     echo '<section style=" border-bottom:1px solid #d9d7d7; padding-left:150px">'.'<input class="label" value="'.$email["address"].'"  name="invite[]" type="checkbox" checked>'.$email["address"]."</section>";
    }
 }
?>

Have you any idea?

What does var_dump($contacts) say ?? – Adam Oct 11 '13 at 08:17 — Adam, Oct 11 '13 at 08:17

score 1 · Answer 1 · edited May 23 '17 at 12:05

1

Yes, general idea is to debug. You should check

var_dump($contacts);

and see what's inside.

It's Friday so may be I'm too kind when doing debug for others

edited May 23 '17 at 12:05

Community

1
1

answered Oct 11 '13 at 08:12

Alma Do

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score 0 · Answer 2 · answered Oct 11 '13 at 08:25

Yes.... I found its solution,

It will be.

<?php
$contacts= $getcontact_access->GetContacts($oauth, $access_token, $access_token_secret, false, true,$emails_count);
if (is_array($contacts))
{
foreach($contacts as $k => $a)
 {
  $final = end($contacts[$k]);
   foreach($final as $email)
    {
      echo '<section style=" border-bottom:1px solid #d9d7d7; padding-left:150px">'.'<input class="label" value="'.$email["address"].'"  name="invite[]" type="checkbox" checked>'.$email["address"]."</section>";
    }
 }
}
?>

Invalid argument supplied for foreach() in 2

2 Answers2