5

I am trying to create 2 tables in the same MySQL database with a PHP-script: table 'user' with primary key 'user_id' and table 'order' with primary key 'order_id' and foreign key 'user_id' from the 'user' table (1 to many relationship).

Table user creates successfully without problems:

$sql="CREATE TABLE user(
    user_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
    type ENUM('member','admin') NOT NULL,
    username VARCHAR(30) NOT NULL,
    email VARCHAR(80) NOT NULL,
    pass VARBINARY(32) NOT NULL,
    first_name VARCHAR(40) NOT NULL,
    last_name VARCHAR(40) NOT NULL,
    date_expires DATE NOT NULL,
    date_created TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
    date_modified TIMESTAMP NOT NULL DEFAULT '0000-00-00 00:00:00',
    PRIMARY KEY (user_id),
    UNIQUE (username),
    UNIQUE (email) 
    )ENGINE=InnoDB DEFAULT CHARSET=utf8";

However, I am not able to create table order:

$sql="CREATE TABLE order(
    order_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
    user_id INT UNSIGNED NOT NULL,
    transaction_id VARCHAR(19) NOT NULL,
    payment_status VARCHAR(15) NOT NULL,
    payment_amount DECIMAL(6,2) UNSIGNED NOT NULL,
    payment_date_time TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
    PRIMARY KEY (order_id),
    FOREIGN KEY (user_id) REFERENCES user (user_id)
    )ENGINE=InnoDB DEFAULT CHARSET=utf8";

I get the following error:

Error creating table: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order( order_id INT UNSIGNED NOT NULL AUTO_INCREMENT, user_id ' at line 1

Already checked the syntax and cannot find the mistake. Could you please advise what went wrong? Thanks a lot.

Bill Karwin
  • 538,548
  • 86
  • 673
  • 828

2 Answers2

9

You need to escape reserved words like order with backticks

CREATE TABLE `order` ( ...

or better use another name instead.

juergen d
  • 201,996
  • 37
  • 293
  • 362
  • Should I always declare my table 'names' in this way? My textbook didn't care so far... –  Oct 11 '13 at 13:10
  • @Neo83 - it's a good habit to get into, same with column names – Mark Baker Oct 11 '13 at 13:11
  • @Neo83: That is up to you. Personally I find it confusing having backticks everywhere. Do as you like. – juergen d Oct 11 '13 at 13:12
  • Just changed the table name to orders and now it works. Wouldn't accept 'order'. Thanks for your help. –  Oct 11 '13 at 13:14
  • @Neo83: You used quotes around `order`. Backticks are different. – juergen d Oct 11 '13 at 13:17
  • Ah, ok. Now I got it. I am using Robin Nixon's "PHP, MySQL, ..." and the syntax he is teaching is far from ideal... Thanks for pointing me in the right direction. –  Oct 11 '13 at 13:21
2

order is keyword used by mysql like (select from tbl_name order by id ASC) so for escaping from using keywords you have to use quotes `` to avoid my sql error

so your query should by 

$sql="CREATE TABLE `order` (
order_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
user_id INT UNSIGNED NOT NULL,
transaction_id VARCHAR(19) NOT NULL,
payment_status VARCHAR(15) NOT NULL,
payment_amount DECIMAL(6,2) UNSIGNED NOT NULL,
payment_date_time TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (order_id),
FOREIGN KEY (user_id) REFERENCES user (user_id)
)ENGINE=InnoDB DEFAULT CHARSET=utf8";

enjoy :D

Ahmed Abumostafa
  • 208
  • 1
  • 7