view contents of a dynamic array in xcode C++ (lldb)

Question

How to view the contents of a dynamically created array in xcode debugger (C++)?

int main(int argc, const char * argv[])
{
int *v;
int size;
cout << "Enter array size" << endl;
cin >> size;
v = new int [size];
for (int i=0; i<size; i++){
    cin >> v [size];
}
// see array contents
return 0;
}

I want to view contents of v.

I think your question is already answered here: http://stackoverflow.com/questions/484707/viewing-a-dynamically-allocated-array-with-the-xcode-debugger — lolando, Oct 12 '13 at 01:12

score 16 · Accepted Answer · answered Oct 14 '13 at 22:12

16

We didn't add some syntax in the expression parser like the gdb "@" syntax because we want to keep the language syntax as close to C/ObjC/C++ as possible. Instead, since the task you want to perform is "read some memory as an array of N elements of type T", you would do this using:

(lldb) memory read -t int -c `size` v

In general, -t tells the type, and -c the number of elements, and I'm using the fact that option values in back ticks are evaluated as expressions and the result substituted into the option.

answered Oct 14 '13 at 22:12

Jim Ingham

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Are there some options to read from specific index to another ? Thanks. – user1673892 Oct 16 '13 at 22:13
1

Not explicitly, though that might be a good idea, but you can put the initial offset in the expression for the start address: `v+5`. – Jim Ingham Oct 18 '13 at 00:49

score 0 · Answer 2 · edited May 23 '17 at 10:32

0

There is a better answer over at another thread.

https://stackoverflow.com/a/26303375/767039

I think this is easier to use and remember.

edited May 23 '17 at 10:32

Community

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answered Apr 21 '15 at 07:43

Nyon

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view contents of a dynamic array in xcode C++ (lldb)

2 Answers2