Make a menu with the names of the files in a directory

Question

I want to make a small extra menu for my website. Is it possible to get the name of the files in a directory and put them in the menu.

So if you have a directory with files: facebook.php; twitter.php; stackoverflow.html; that you will get a menu like this:

facebook
twitter
stackoverflow

And if it's possible I want to choose that what kind of files he gets. So I want him to get the name of .php and .html files but not of .css files.

Can somebody help me with this?

This question has been asked before - http://stackoverflow.com/questions/8541180/best-way-to-get-files-from-a-dir-filtered-by-certain-extension-in-php — Terry, Oct 12 '13 at 15:28

score 3 · Accepted Answer · answered Oct 12 '13 at 16:09

3

I like glob():

foreach(glob("$dir/{*.php,*.html}", GLOB_BRACE) as $file) {
    //whatever
}

or

$files = glob("$dir/{*.php,*.html}", GLOB_BRACE); //then use $files wherever

You can use pathinfo() with PATHINFO_BASENAME to get only filename PATHINFO_FILENAME to get it without the extension.

answered Oct 12 '13 at 16:09

AbraCadaver

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Now i know how to get the file names, but do you also know how i can put each filename in a other li? I'm not really good with php but I want to learn it. – Moreno__R Oct 12 '13 at 20:47
1

@Moreno__R: In the first example just replace //whatever with `echo "
".pathinfo($file, PATHINFO_FILENAME)."

AbraCadaver

Oct 13 '13 at 00:09

score 0 · Answer 2 · answered Oct 12 '13 at 15:33

Try the scandir() method

In the loop check the current file is a directory with is_dir(). And then you can get the path with [dirname]/[dirname.php]. Check if an exist file, and then you can display the link.

$files = scandir('menus');
$links = array();
foreach ($files as $file) {
   if ($file == "." || $file == "..")
      continue;

   if (is_dir($file)) {
      $menuFile = "./menus/$file/$file.php";
      if (is_file($menuFile)) {
         $links[$file] = $menuFile;
      }
   }
}

//display the links

Make a menu with the names of the files in a directory

2 Answers2