Keep getting Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result resource

Question

In my PHP code, I get this error on line 12 whenever I try to run it. (Code below ((obviously))

It tells me that mysql_fetch_object(): is not a valid MySQL result resource, but I have tried 4 PHP syntax checkers and all is well.

Thank you, and please help, thanks!

This is my code that I believe contains the error

<?
$connection = mysql_connect('localhost', 'socialli_main2', 'password+',  `'socialli_main');
mysql_select_db(`Users`);
$ID = mysql_real_escape_string(strip_tags(stripslashes($_GET['ID'])));
$Username = mysql_real_escape_string(strip_tags(stripslashes($_GET['Username'])));
if (!$Username) {
$getUser = mysql_query("SELECT * FROM Users WHERE ID='".$ID."'");
}
else {
$getUser = mysql_query("SELECT * FROM Users WHERE Username='".$Username."'");
}
$gU = mysql_fetch_object($getUser);

Can you tell me if there are any typos or anything in my code? thanks — user2896692, Oct 18 '13 at 23:59
The linked answer tells you how to do some very basic debugging for mysql errors on your own – so please do that. — CBroe, Oct 19 '13 at 00:00
you have a typo on your first line in the end of mysql_connect — CIRCLE, Oct 19 '13 at 00:00
@user2896692: It's on the first line. Please **read** the entire line. We can't spoonfeed you. ;) — Amal Murali, Oct 19 '13 at 00:05
I found a random backtick at the end and removed, is that the error? — user2896692, Oct 19 '13 at 00:08
do you have a typo or is this the actual code you are showing? — Ibu, Oct 19 '13 at 00:19

score 0 · Answer 1 · answered Oct 19 '13 at 00:45

0

$connection = mysql_connect('localhost', 'socialli_main2', 'password+', Here -->`'socialli_main'); =)

answered Oct 19 '13 at 00:45

Jose Almeida

54
1
6

Keep getting Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result resource

1 Answers1