What's wrong with this Java Coded if STatement?

Question

I am not a professional programer. I am still learning, so my code is a little basic right now.

Scanner UserInput = new Scanner(System.in);
String UserChoose = UserInput.next();
if (UserChoose=="Quit"){

I have deduced that there is something missing in the if statement, but I cannot figure out what. Can someone please tell me what I am missing? I have been searching online for an hour with no luck.

Justin Lessard · Answer 1 · 2013-10-20T16:28:05.763

0

if (UserChoose.equals("Quit")){

In java, the default == operator compare if they both are the same object, even if the content is the same, if the object reference is not the same, it isn't ==.

See this link for more complete explanation: http://blog.enrii.com/2006/03/15/java-string-equality-common-mistake/

edited Oct 20 '13 at 16:28

answered Oct 20 '13 at 16:22

Justin Lessard

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small `e` for `equals` – Oct 20 '13 at 16:23

score 0 · Answer 2 · answered Oct 20 '13 at 16:23

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To compare objects in java use .equals() method instead of "==" operator

Replace if (UserChoose=="Quit"){ with if (UserChoose.equals("Quit")){

answered Oct 20 '13 at 16:23

Prabhakaran Ramaswamy

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score 0 · Answer 3 · answered Oct 20 '13 at 16:24

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Common mistake, use UserChoose.equals("Quit") to compare strings. Since String is an object, using == will likely compare the memory location the 2 strings or something that would always result with false.

answered Oct 20 '13 at 16:24

ThaBomb

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What's wrong with this Java Coded if STatement?

3 Answers3