user input string and integers in Java

Question

    System.out.print("Name : ");
    String name = in.nextLine();

    System.out.print("Age : ");
    int age = in.nextInt();

    System.out.print("City : ");
    String city = in.nextLine();

the output will be :

Name : test

Age : 20

BUILD SUCCESSFUL

when i debug them, it won't read the user input for "city" . but when i changed the data type for "age" to string, it will read. how can i kept the data type of age to int with the system reading the user inputs for city ?

@athirahhazira94 , you have go through on about nextLine(). Anda kena baca tentang nextLine(). — gjman2, Oct 21 '13 at 03:02

Scary Wombat · Accepted Answer · 2013-10-21T02:44:05.670

8

As there is still a new line character in the buffer after reading the age, change it to..

System.out.print("Name : ");
String name = in.nextLine();

System.out.print("Age : ");
int age = in.nextInt();
//add
in.nextLine();

System.out.print("City : ");
String city = in.nextLine();

edited Oct 21 '13 at 02:44

answered Oct 21 '13 at 02:35

Scary Wombat

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It might be helpful to post *why* that addition is necessary, just for anyone else who comes across this question. – Dennis Meng Oct 21 '13 at 02:36
yes . i agree with @dennis . why does it necessary ? – Athirah Hazira Oct 21 '13 at 02:38
I agree too, so it is now done – Scary Wombat Oct 21 '13 at 02:44

MadProgrammer · Answer 2 · 2013-10-21T06:19:16.423

1

There is still a new line character in the buffer after reading the age. Try adding a in.nextLine before you ask for the city value.

edited Oct 21 '13 at 06:19

answered Oct 21 '13 at 02:36

MadProgrammer

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score 1 · Answer 3 · answered Oct 21 '13 at 02:40

1

Try this,

System.out.print("Age : ");
int age = Integer.parseInt(in.nextLine());

answered Oct 21 '13 at 02:40

newuser

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user input string and integers in Java

3 Answers3

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