How to find and replace all characters in a string with specific symbols C++

Question

I am a beginner in programming so take it easy if i approached the problem in a wrong way. i am doing this as an assignment. My purpose is to take a string from user and replace all the characters with another symbol. The code below is supposed to find all the As and replace then with *s. My code is showing totally unexpected result. Also what is the purpose of _deciphered.length().

for example: "I Am A bAd boy" should turn into "I *m * b*d boy"

then i am supposed to implement it for all capital and small letters and numbers and replace with different symbols and vice versa to make a small Encode-Decode program

#include <iostream>
#include <string>
using namespace std;
string cipher (string);
void main ()
{

    string ciphered, deciphered;
    ciphered="String Empty";
    deciphered="String Empty";
    cout<<"Enter a string to \"Encode\" it : ";
    cin>>deciphered;
    ciphered=cipher (deciphered);
    cout<<endl<<endl;
    cout<<deciphered;
}
string cipher (string _deciphered)
{
    string _ciphered=(_deciphered.replace(_deciphered.find("A"), _deciphered.length(), "*"));
    return _ciphered;
}

juanchopanza · Accepted Answer · 2013-10-23T19:17:13.050

4

Since you seem to be using the standard library already,

#include <algorithm> // for std::replace

std::replace(_deciphered.begin(), _deciphered.end(), 'A', '*');

If you need to do this by hand, then bear in mind that an std::string looks like a container of char, so you can iterate over its contents, check if each element is 'A', and if so, set it to '*'.

Working example:

#include <iostream>
#include <string>
#include <algorithm>

int main()
{
  std::string s = "FooBarro";
  std::cout << s << std::endl;
  std::replace(s.begin(), s.end(), 'o', '*');
  std::cout << s << std::endl;
}

Output:

FooBarro

F**Barr*

edited Oct 23 '13 at 19:17

answered Oct 23 '13 at 15:48

juanchopanza

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this only works till it finds first a and returns only that word. eg if i enter "bad bay" it returns "b*d". how do i get it to return complete string "b*d b*y"? – Usama Khurshid Oct 23 '13 at 17:28
@UsamaKhurshid no, you are mistaken. It will replace all `A` characters by `*`. – juanchopanza Oct 23 '13 at 19:12
@UsamaKhurshid I tried it. Either you are trying something else or your std library implementation is broken. – juanchopanza Oct 23 '13 at 21:28
the solution that u posted now works! thanks.. i wonder what was wrong with the first one you posted! – Usama Khurshid Oct 23 '13 at 21:31

score 1 · Answer 2 · answered Oct 23 '13 at 15:49

You can use std::replace

std::replace(deciphered.begin(), deciphered.end(), 'A', '*');

Also, you can use std::replace_if if you want to replace multiple values that match a certain criteria.

std::replace_if(deciphered.begin(), deciphered.end(), myPredicate, '*');

where myPredicate returns true if the character matches the criteria to be replaced. So for example, if you want to replace both a and A, myPredicate should return true for a and A and false for other characters.

score 0 · Answer 3 · edited May 23 '17 at 11:50

0

I would personally use regular experssion replace to repace "A or a" with *

Have a look at this answer for some pointers: Conditionally replace regex matches in string

edited May 23 '17 at 11:50

Community

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answered Oct 23 '13 at 15:52

Brian

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While a regular expression could be used, `std::replace` is much simpler and has much less overhead. – Pete Becker Oct 23 '13 at 16:05

How to find and replace all characters in a string with specific symbols C++

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