Converting Youtube Data API V3 video duration format to standard time in PHP

Question

I'm, getting this array from a youtube API request, but the duration format is very rare in my opinion. Why didn't they just throw seconds in there? In any case this is the array

[duration] => PT2M3S
[dimension] => 2d
[definition] => sd
[caption] => false

Is there a way to convert this duration to a "H:i:s" format in PHP?

Thanks in advance for your help

score 7 · Answer 1 · edited Aug 11 '17 at 11:15

7

acidjazz has a great solution, but there is a typo where it displays the minutes. It should be $di->i for minutes, not $di->m. You can also remove the "public static" portion if you're not using it in an object, and I took out the sprintf().

Otherwise the function works as is:

function duration($ytDuration) {

    $di = new DateInterval($ytDuration);
    $string = '';

    if ($di->h > 0) {
      $string .= $di->h.':';
    }

    return $string.$di->i.':'.$di->s;
}

I would have added this as a comment to his answer, but there's the whole "You need 50 reputation to comment" BS that prevents me from sticking to the flow of this thread.

edited Aug 11 '17 at 11:15

Muhammad Hassaan

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answered Sep 16 '14 at 14:39

James

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Yes, it's correctly result. However, in my case. I always use sprintf('%02s', 'xx') in all hour, minute, second. (xx means those unit). If no zero leading the result might be 1:2:6 for 1 hour 2 minutes 6 seconds. It looks strange for 1:2:6. Thank you for this answer. – vee Aug 26 '15 at 11:42

Andrew · Accepted Answer · 2013-10-24T10:09:33.610

5

In fact it is simple ISO8601 date. Split string with regexp like (\d+) to minutes and seconds. Then get integer part of division of minutes by 60 to get hours. Get remainder of that division to get minutes.

here is an example that should work though i didn't tested it

preg_match_all('/(\d+)/',$youtube_time,$parts);

$hours = floor($parts[0][0]/60);
$minutes = $parts[0][0]%60;
$seconds = $parts[0][1];

edited Oct 24 '13 at 10:09

answered Oct 24 '13 at 10:00

Andrew

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4

Thanks for the approach, at the end I did this. `code` $duration = new DateInterval($videoData['duration']); $videoDuration = (60 * 60 * $duration->h) + (60 * $duration->i) + $duration->s; print gmdate("H:i:s", $videoDuration); – user2915047 Oct 24 '13 at 10:31
this will get wrong data if you have schema like that : PT54S , youtube will give you this duration if video less than 1 minute – Yahia Oct 03 '14 at 09:43

acidjazz · Answer 3 · 2014-01-24T22:59:34.300

4

You can use php's DateInterval Class to parse it properly. For example a function in a youtube wrapper class to parse it to the format YouTube displays might look like:

  public static function duration($ytDuration) {

    $di = new DateInterval($ytDuration);
    $string = '';

    if ($di->h > 0) {
      $string .= $di->h.':';
    }

    return $string.$di->m.':'.sprintf('%02s',$di->s);
  }

edited Jan 24 '14 at 22:59

answered Jan 24 '14 at 22:53

acidjazz

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score 3 · Answer 4 · edited May 23 '17 at 12:00

I used @chris-z-s 's answer here , and converted it to php :

function getDurationSeconds($duration){
    preg_match_all('/[0-9]+[HMS]/',$duration,$matches);
    $duration=0;
    foreach($matches as $match){
        //echo '<br> ========= <br>';       
        //print_r($match);      
        foreach($match as $portion){        
            $unite=substr($portion,strlen($portion)-1);
            switch($unite){
                case 'H':{  
                    $duration +=    substr($portion,0,strlen($portion)-1)*60*60;            
                }break;             
                case 'M':{                  
                    $duration +=substr($portion,0,strlen($portion)-1)*60;           
                }break;             
                case 'S':{                  
                    $duration +=    substr($portion,0,strlen($portion)-1);          
                }break;
            }
        }
    //  echo '<br> duratrion : '.$duration;
    //echo '<br> ========= <br>';
    }
     return $duration;

}

it worked with me :)

score 1 · Answer 5 · answered Dec 06 '16 at 12:45

1

May be it will be helpful for someone to get duration:

$interval = new \DateInterval($iso8601);

// in seconds:
$seconds = $interval->h * 360 + $interval->i * 60 + $interval->s;

// in "H:i:s" format:
echo $interval->format('%H:%i:%s');

answered Dec 06 '16 at 12:45

D.Dimitrioglo

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score 0 · Answer 6 · answered Nov 20 '13 at 17:31

this is my solution:

preg_match('/(\d+)H/', $duration, $match);
$h = ($match[0])?filter_var($match[0], FILTER_SANITIZE_NUMBER_INT).":":'';
preg_match('/(\d+)M/', $duration, $match);
$m = filter_var($match[0], FILTER_SANITIZE_NUMBER_INT).":";
preg_match('/(\d+)S/', $youtube_date, $match);
$s = filter_var($match[0], FILTER_SANITIZE_NUMBER_INT);
echo: "Duration: " . $h.$m.$s;

score 0 · Answer 7 · answered Dec 03 '13 at 22:39

##:##:## Time format on PHP

 function NormalizeDuration($duration){
    preg_match('#PT(.*?)H(.*?)M(.*?)S#si',$duration,$out);
    if(empty($out[1])){
    preg_match('#PT(.*?)M(.*?)S#si',$duration,$out);
    if(empty($out[1])){
    preg_match('#PT(.*?)S#si',$duration,$out);
    if(empty($out[1])){
    return '00:00';
    }
    }else{
    if(strlen($out[1])==1){ $out[1]= '0'.$out[1]; }
    if(strlen($out[2])==1){ $out[2]= '0'.$out[2]; }
    return $out[1].':'.$out[2];
    }
    }else{
    if(strlen($out[1])==1){ $out[1]= '0'.$out[1]; }
    if(strlen($out[2])==1){ $out[2]= '0'.$out[2]; }
    if(strlen($out[3])==1){ $out[3]= '0'.$out[3]; }
    return $out[1].':'.$out[2].':'.$out[3];
    }
    }

score 0 · Answer 8 · answered Jul 16 '15 at 14:13

Use the following php function will return the YouTube video duration..For more exciting codes follow this link more code samples

    function getYoutubeDuration($vid) 
    {
    $videoDetails =file_get_contents("https://www.googleapis.com/youtube/v3/videos?id=".$vid."&part=contentDetails&key=AIzaSyDen99uTRRPl9VT_Ra9eAisvZSc4aZDEns");
    $videoDetails =json_decode($videoDetails, true);
    foreach ($videoDetails['items'] as $vidTime)
     {
        $youtube_time = $vidTime['contentDetails']['duration'];
        preg_match_all('/(\d+)/',$youtube_time,$parts);
        $hours = (strlen(floor($parts[0][0]/60))<1)?floor($parts[0][0]/60):'0'.floor($parts[0][0]/60);
        $minutes = $parts[0][0]%60; (strlen($parts[0][0]%60)<1)?$parts[0][0]%60:'0'.$parts[0][0]%60;
        $seconds = $parts[0][1];(strlen($parts[0][1])<1)?$parts[0][1]:'0'.$parts[0][1];
        return $hours.":".$minutes.":".$seconds;
     }
    }

  echo getYoutubeDuration('J1lb3qJgfho');

Tempus · Answer 9 · 2017-02-26T14:52:21.410

As YouTube (Google) like to be difficult, they opt for non-standard formatting. So standard functions don't always work.

As such, I made this for my need's.

$length = $data['items'] ..... ['duration'];

$seconds = substr(stristr($length, 'S', true), -2, 2);
$seconds = preg_replace("/[^0-9]/", '', $seconds);
$minutes =  substr(stristr($length, 'M', true), -2, 2);
$minutes = preg_replace("/[^0-9]/", '', $minutes);
$hours =  substr(stristr($length, 'H', true), -2, 2);
$hours = preg_replace("/[^0-9]/", '', $hours);

Alex · Answer 10 · 2018-07-16T11:22:32.873

Solution with named groups

PT((?P<hours>\d+)H)?((?P<minutes>\d+)M)?((?P<seconds>\d+)S)?

Examples can be found here https://regex101.com/r/wU3hT2/114

Python function:

def yt_time_to_seconds(time):
    regex_string = 'PT((?P<hours>\d+)H)?((?P<minutes>\d+)M)?((?P<seconds>\d+)S)?'
    regex = re.compile(regex_string)
    match = regex.match(time)
    if match:
        hours = int(match.group('hours'))
        minutes = int(match.group('minutes'))
        seconds = int(match.group('seconds'))
        return hours * 60 * 60 + minutes * 60 + seconds
    return 0

score 0 · Answer 11 · edited Oct 05 '18 at 11:30

0

it worked perfectly for me 100%, only you should have \ DateInterval as root

function NormalizeDuration($duration){ //pass your time
    $start = new \DateTime('@0');
    $start->add(new \DateInterval($duration));

    return $start->format('H:i:s'); //format
}

edited Oct 05 '18 at 11:30

cakan

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answered Oct 05 '18 at 10:13

Igor Eremenko

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Converting Youtube Data API V3 video duration format to standard time in PHP

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