93

Edit

It's now fixed on
Don't do any tweak to fix it.

Edit2

Apparently the same problem happens again in iOS 8.0 and 8.1

Edit3

It's now fixed on
Don't do any tweak to fix it.


Hi Today i seen in UISwitch's Event ValueChanged: Calling continuously while i am change to On to Off or Off to On and my finger moved still on right side as well as left side. I atteched GIF image for more clear with NSLog.

enter image description here

My Value Changed Method is:

- (IBAction)changeSwitch:(id)sender{

    if([sender isOn]){
        NSLog(@"Switch is ON");
    } else{
        NSLog(@"Switch is OFF");
    }
    
}

iOS6 the same code of Switch working Fine as we expectation:

enter image description here

so can anyone suggest me that call only one time its state On or off. or is this is a bug or what..?

UPDATE

Here it is my Demo of it:

programmatic Add UISwitch

from XIB adding UISwitch

Community
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Nitin Gohel
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12 Answers12

45

Please see the following code:

-(void)viewDidLoad
{
    [super viewDidLoad];    
    UISwitch *mySwitch = [[UISwitch alloc] initWithFrame:CGRectMake(130, 235, 0, 0)];    
    [mySwitch addTarget:self action:@selector(changeSwitch:) forControlEvents:UIControlEventValueChanged];
    [self.view addSubview:mySwitch];
}

- (void)changeSwitch:(id)sender{
    if([sender isOn]){
        NSLog(@"Switch is ON");
    } else{
        NSLog(@"Switch is OFF");
    }
}
casillas
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AeroStar
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  • thx for answer as i said i was trying both way and got same result. atlist i knw how to add swtich programmatic as well as from xib sir. – Nitin Gohel Oct 28 '13 at 07:40
12

Same bug here. I think I've found a simple workaround. We just have to use a new BOOL that stores the previous state of the UISwitch and an if statement in our IBAction (Value Changed fired) to check that the value of the switch has actually changed.

previousValue = FALSE;

[...]

-(IBAction)mySwitchIBAction {
    if(mySwitch.on == previousValue)
        return;
    // resetting the new switch value to the flag
    previousValue = mySwitch.on;
 }

No more weird behaviors. Hope it helps.

nnarayann
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12

You can use the UISwitch's .selected property to make sure your code only executes once when the value actual changes. I think this is a great solution because it avoids having to subclass or add new properties.

 //Add action for `ValueChanged`
 [toggleSwitch addTarget:self action:@selector(switchTwisted:) forControlEvents:UIControlEventValueChanged];

 //Handle action
- (void)switchTwisted:(UISwitch *)twistedSwitch
{
    if ([twistedSwitch isOn] && (![twistedSwitch isSelected]))
    {
        [twistedSwitch setSelected:YES];

        //Write code for SwitchON Action
    }
    else if ((![twistedSwitch isOn]) && [twistedSwitch isSelected])
    {
        [twistedSwitch setSelected:NO];

        //Write code for SwitchOFF Action
    }
}

And here it is in Swift:

func doToggle(switch: UISwitch) {
    if switch.on && !switch.selected {
        switch.selected = true
        // SWITCH ACTUALLY CHANGED -- DO SOMETHING HERE
    } else {
        switch.selected = false
    }
}
zekel
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itsji10dra
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    I find this one to be simplest. – zekel Feb 10 '16 at 21:31
  • +1'd this because it led me to using a similar solution of populating the .tag value when I want to ignore the toggle logic. I need the logic to fire sometimes in both on and off mode so the above wasn't quite sufficient. – davidethell Mar 24 '17 at 20:40
9

If you are using so many switch in your app then there is problem to change the code in all places where t action method of UISwitch is defined.You can make custom switch and handle the events only if value change.

CustomSwitch.h

#import <UIKit/UIKit.h>

@interface Care4TodayCustomSwitch : UISwitch
@end

CustomSwitch.m

@interface CustomSwitch(){
    BOOL previousValue;
}
@end

@implementation CustomSwitch



- (id)initWithFrame:(CGRect)frame
{
    self = [super initWithFrame:frame];
    if (self) {
        // Initialization code
        previousValue = self.isOn;
    }
    return self;
}


-(void)awakeFromNib{
    [super awakeFromNib];
    previousValue = self.isOn;
    self.exclusiveTouch = YES;
}


- (void)setOn:(BOOL)on animated:(BOOL)animated{

    [super setOn:on animated:animated];
    previousValue = on;
}


-(void)sendAction:(SEL)action to:(id)target forEvent:(UIEvent *)event{

    if(previousValue != self.isOn){
        for (id targetForEvent in [self allTargets]) {
            for (id actionForEvent in [self actionsForTarget:targetForEvent forControlEvent:UIControlEventValueChanged]) {
                [super sendAction:NSSelectorFromString(actionForEvent) to:targetForEvent forEvent:event];
            }
        }
        previousValue = self.isOn;
    }
}

@end

We are ignoring events if the value is same as changed value.Put CustomSwitch in all the class of UISwitch in storyboard.This will resolve the issue and call target only once when value changed

codester
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  • This worked for me. It's ideal in that it does not cause extraneous code to be manually added in your implementation files, as it's reusable and hides its implementation inside the class implementation. This is just good design. It would be nice if this answer had more comments though, because I don't really understand why all of the code is there. – James C Apr 22 '15 at 17:24
  • Thanks, it worked for me. Can you explain the code a little bit more. @codester – Swayambhu Dec 17 '15 at 15:30
7

I got many user that facing same issue so may be this is bug of UISwitch so i found just now for temporary solution of it. I Found one gitHub custom KLSwitch use this for now hope apple will fix this in next update of xCode:-

https://github.com/KieranLafferty/KLSwitch

Nitin Gohel
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6

If you don't need to react instantly to the switch's value change the following could be a solution:

- (IBAction)switchChanged:(id)sender {
  [NSObject cancelPreviousPerformRequestsWithTarget:self];

  if ([switch isOn]) {
      [self performSelector:@selector(enable) withObject:nil afterDelay:2];
  } else {
      [self performSelector:@selector(disable) withObject:nil afterDelay:2];
  }
}
pre
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  • Worked like a charm in iOS 11.2. In my situation, it fired 2 events in a row (state: off, swiping: off, 1st event: on, 2nd event: off), so a delay of 0.1s is enough for me and not noticeable to a user. – Paul Semionov Dec 13 '17 at 15:04
3

This issue is still here as of iOS 9.3 beta. If you don't mind the user not being able to drag outside of the switch, I find that using .TouchUpInside rather than .ValueChanged works reliably.

Nick Kohrn
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2

I am still facing same problem in iOS 9.2

I got solution and posing as it might help others

  1. Create count variable to trace number of times method got call

    int switchMethodCallCount = 0;
    
  2. Save bool value for switch value

    bool isSwitchOn = No;
    
  3. In Switch's value change method perform desire action for first method call only. When switch value again changes set count value andt bool variable value to default

    - (IBAction)frontCameraCaptureSwitchToggle:(id)sender {
    
    
    
    //This method will be called multiple times if user drags on Switch,
    //But desire action should be perform only on first call of this method
    
    
    //1. 'switchMethodCallCount' variable is maintain to check number of calles to method,
    //2. Action is peform for 'switchMethodCallCount = 1' i.e first call
    //3. When switch value change to another state, 'switchMethodCallCount' is reset and desire action perform
    
    switchMethodCallCount++ ;
    
    //NSLog(@"Count --> %d", switchMethodCallCount);
    
    if (switchMethodCallCount == 1) {
    
    //NSLog(@"**************Perform Acction******************");
    
    isSwitchOn = frontCameraCaptureSwitch.on
    
    [self doStuff];
    
    }
    else
    {
    //NSLog(@"Do not perform");
    
    
    if (frontCameraCaptureSwitch.on != isSwitchOn) {
    
        switchMethodCallCount = 0;
    
        isSwitchOn = frontCameraCaptureSwitch.on
    
        //NSLog(@"Count again start");
    
        //call value change method again 
        [self frontCameraCaptureSwitchToggle:frontCameraCaptureSwitch];
    
    
        }
    }
    
    
    }
    
Chetan Koli
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  • I, too, am still facing this issue in 9.2. I implemented your logic, and now it is working as I had intended. – Nick Kohrn Feb 02 '16 at 02:54
2

This problem plagues me when I tie the switch to other behaviors. Generally things don't like to go from on to on. Here's my simple solution:

@interface MyView : UIView
@parameter (assign) BOOL lastSwitchState;
@parameter (strong) IBOutlet UISwitch *mySwitch;
@end

@implementation MyView

// Standard stuff goes here

- (void)mySetupMethodThatsCalledWhenever
{
    [self.mySwitch addTarget:self action:@selector(switchToggled:) forControlEvents:UIControlEventValueChanged];
}

- (void)switchToggled:(UISwitch *)someSwitch
{
    BOOL newSwitchState = self.mySwitch.on;
    if (newSwitchState == self.lastSwitchState)
    {
        return;
    }
    self.lastSwitchState = newSwitchState;

    // Do your thing
}

Just be sure to also set self.lastSwitchState every time you manually change mySwitch.on! :)

Ky -
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1

This type of problem is often caused by ValueChanged. You don't need to press the button to cause the function to run. It's not a touch event. Every time you programmatically change the switch to on/off, the value changes and it calls the IBAction function again.

@RoNiT had the right answer with:

Swift

func doToggle(switch: UISwitch) {
    if switch.on && !switch.selected {
        switch.selected = true
        // SWITCH ACTUALLY CHANGED -- DO SOMETHING HERE
    } else {
        switch.selected = false
    }
}
Dave G
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0
DispatchQueue.main.async {
        self.mySwitch.setOn(false, animated: true)
    }

This works fine and doesn't calls the selector function again.

anuraagdjain
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0

This worked for me.

DispatchQueue.main.asyncAfter(deadline: DispatchTime.now()){
    self.switch.isOn = true
}
barbsan
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user3305074
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