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I'm advancing in jee programming. From basic tutorials if I want read my application directory in class extending HttpServlet I use getServletContext().getRealPath(relativePath). But In my case I used Jersey for serialization purposes. Servlet not extending HttpServlet, look at imageenter image description here . I'm mainly front programmer so maybe it is stupid question, but I want simple static/util method for resolving pathes to different static resources in my webapp. I run it on Tomcat. One and only servlet as on image.

RobertW
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2 Answers2

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As per specs (JAX-RS 1.1, ch. 6.1), add this in your resource class:

@Context
private ServletContext application;

The fully quallified names are:

import javax.servlet.ServletContext;
import javax.ws.rs.core.Context;
Nikos Paraskevopoulos
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  • Context bindinding is manged by container so if I tried use it servlet constructor or static method context was null. – RobertW Oct 30 '13 at 09:12
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The absolute path to your webApp/WEB-INF/classes directory can be accessed as below:

URL resource = getClass().getResource("/");
String path = resource.getPath();

This will return you an absolute path like this:

/C:/SERVERS/x/y/x/yourApp/WEB-INF/classes

And from this you can get the path to the webapp directory:

path = path.replace("WEB-INF/classes/", "");

Now if your static resource is directly under webapp, you can access that resource with this:

path = path + "resource_name";
Debojit Saikia
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  • Looks simple and right. I will try it later. Now I found that my ressource must be outside webapp direcoty. – RobertW Oct 30 '13 at 09:15