Because ret
is NOT the proper way to exit a program in Linux, Windows, or Mac!!!!
_start
is not a function, there is no return address on the stack because there is no user-space caller to return to. Execution in user-space started here (in a static executable), at the process entry point. (Or with dynamic linking, it jumped here after the dynamic linker finished, but same result).
On Linux / OS X, the stack pointer is pointing at argc
on entry to _start
(see the i386 or x86-64 System V ABI doc for more details on the process startup environment); the kernel puts command line args into user-space stack memory before starting user-space. (So if you do try to ret
, EIP/RIP = argc = a small integer, not a valid address. If your debugger shows a fault at address 0x00000001
or something, that's why.)
For Windows it is ExitProcess
and Linux is is system call -
int 80H
using sys_exit
, for x86 or using syscall
using 60
for 64-bit or a call to exit
from the C Library if you are linking to it.
32-bit Linux (i386)
%define SYS_exit 1 ; call number __NR_exit from <asm/unistd_32.h>
mov eax, SYS_exit ; use the NASM macro we defined earlier
xor ebx, ebx ; ebx = 0 exit status
int 80H ; _exit(0)
64-bit Linux (amd64)
mov rax, 60 ; SYS_exit aka __NR_exit from asm/unistd_64.h
xor rdi, rdi ; edi = 0 first arg to 64-bit system calls
syscall ; _exit(0)
(In GAS you can actually #include <sys/syscall.h>
or <asm/unistd.h>
to get the right numbers for the mode you're assembling a .S
for, but NASM can't easily use the C preprocessor.
See Polygot include file for nasm/yasm and C for hints.)
32-bit Windows (x86)
push 0
call ExitProcess
Or Windows/Linux linking against the C Library
; pass an int exit_status as appropriate for the calling convention
; push 0 / xor edi,edi / xor ecx,ecx
call exit
(Or for 32-bit x86 Windows, call _exit
, because C names get prepended with an underscore, unlike in x86-64 Windows. The POSIX _exit
function would be call __exit
, if Windows had one.)
Windows x64's calling convention includes shadow space which the caller has to reserve, but exit
isn't going to return so it's ok to let it step on that space above its return address. Also, 16-byte stack alignment is required by the calling convention before call exit
except for 32-bit Windows, but often won't actually crash for a simple function like exit()
.
call exit
(unlike a raw exit system call or libc _exit
) will flush stdio buffers first. If you used printf
from _start
, use exit
to make sure all output is printed before you exit, even if stdout is redirected to a file (making stdout full-buffered, not line-buffered).
It's generally recommended that if you use libc functions, you write a main
function and link with gcc so it's called by the normal CRT start functions which you can ret
to.
See also
Defining main
as something that _start
falls through into doesn't make it special, it's just confusing to use a main
label if it's not like a C main
function called by a _start
that's prepared to exit after main
returns.