Take filename as password value in script

Question

I have multiple password protected files in a directory eg:

file123.dat
file456.dat
file789.dat etc

I will be writing a script in linux to extract them with their passwords. each file has its own filename as password how can i extract the names of the files and put them in the script? NOTE:the password are certain alphabets from the filename and not the entire filename I am using 7zip to extract the file. The script i am using now is :

#!/bin/bash
FILES=`ls *.zip | xargs -r`
for FILE in $FILES; do
PASSWD=`echo $FILE | awk '{print substr($0,1,2)}'`
`echo abc``echo $FILE | awk '{print       substr($0,5,2)}'`

7za X -p $PASSWD $Z_FILE //using 7zip to unzip
if [ $? = 0 ]; then # successful unzip
break
fi
done
done

Give us an example of how it's store that data into the files... — DontVoteMeDown, Nov 05 '13 at 16:25
What do you extract with, zip, [bzip2](http://en.wikipedia.org/wiki/Bzip2) or [something else](http://en.wikipedia.org/wiki/List_of_archive_formats)? Also, what have you tried? — miku, Nov 05 '13 at 16:25
possible duplicate of [Bash Script to Execute Command on All Files in Directory](http://stackoverflow.com/questions/10523415/bash-script-to-execute-command-on-all-files-in-directory) — Marc B, Nov 05 '13 at 16:25

score 0 · Accepted Answer · answered Nov 05 '13 at 16:27

0

#!/bin/bash
FILES=`ls *.dat | xargs -r`
for FILE in $FILES; do
    PASSWD=`echo $FILE | sed 's/.dat//'`
     ## extract file $FILE using password $PASSWD
done

answered Nov 05 '13 at 16:27

Claudio

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2

1) Don't parse `ls`: just use `for FILE in *.dat; do`. 2) Don't use `sed` when the parameter expansion `PASSWD=${FILE%.dat}` does the same thing. – chepner Nov 05 '13 at 17:12
and don't use backticks and don't use uppercase variable names. – gniourf_gniourf Nov 05 '13 at 18:48
When i try to extract the files with the above code it does not work any suggestions – Rahul sawant Nov 05 '13 at 18:48

Take filename as password value in script

1 Answers1