Checking if the input value is integer type java

Question

I am requesting users input where he needs to write integers. I managed to create validation that checks if the value is higher than needed and so, with this code :

int n = sca.nextInt(); 
while (n<=0){
    System.err.println(error_1);
    n = sca.nextInt(); 
}

But now how to add check for strings, I found such solution How do I keep a Scanner from throwing exceptions when the wrong type is entered?

That uses hasNextInt() before actually reading the input, I tried to put this check inside while loop in the same place with n<=0 like this

while ( (n<=0)||(sca.hasNextInt() )) {
  ....
}

But it responded with error that variable n is not compatible with that method. So is there any way to overcome such thing?

Can we get the exact error message? (and if possible a small, complete example that still shows your problem) — Dennis Meng, Nov 05 '13 at 18:13
"variable n is not compatible with that method": I am sure this was not the exact error message. What did you get? — Henry, Nov 05 '13 at 18:14
@Dennis Meng I am sorry guys, but I can't recreate the error. Is there way to find previus compiling errors ? — Edgars, Nov 05 '13 at 18:26
Are you able to reproduce the error at all? If not, then there's not much help any of this is going to be able to do. — Dennis Meng, Nov 05 '13 at 18:28

score 5 · Answer 1 · answered Nov 05 '13 at 18:25

5

You can use parseInt and check exception:

public boolean parseWithFallback(String text) {
try {
  Integer.parseInt(text);
  return true;
} catch (NumberFormatException e) {
 return false;
 } 
}

answered Nov 05 '13 at 18:25

ArturSkowronski

1,722
13
17

lkamal · Accepted Answer · 2013-11-05T20:45:02.223

3

First invocation of nextInt() also can result in an exception, if you do not check whether the input is of int type.

Hope below will resolve your issue.

Scanner sca = new Scanner(System.in);

boolean incorrectInput = true;
int userInput = -1; // initialize as a negative  

while (incorrectInput) {

    if (sca.hasNextInt()) {
        int n = sca.nextInt();
        if (n < 0) {
            System.err.println("error_1");
        } else {
            // do anything else
            userInput = n;
            incorrectInput = false;
        }
    } else {
        sca.next();
    }
}

if (!incorrectInput) {
    System.out.println("UserInput = " + userInput);
}

edited Nov 05 '13 at 20:45

answered Nov 05 '13 at 18:32

lkamal

3,788
1
20
34

@Ikamal IT is almost there, just need to resolve that the program methods that is below this code cannot access to n variable :(But anyway thanks for this – Edgars Nov 05 '13 at 20:05
@Ikamal Is there any ideas, because I tried to change n variable location , but no succes ;( – Edgars Nov 05 '13 at 20:22
@EdgarsRozenfelds Updated the code to allow access to the user input outside the while loop using a new variable named `userInput`. – lkamal Nov 05 '13 at 20:46

Simulant · Answer 3 · 2013-11-05T19:09:44.593

1

You have to test if there is a next Int before trying to get the next Int.

boolean finished = false;
while(!finished){
  while(scan.hasNextInt()){
    int n = sca.nextInt(); 
    if(n <= 0){
      System.out.println("Error: Number smaller 0");
    } else {
      System.out.println("correct!");
      finished = true;
    }
  }
}

edited Nov 05 '13 at 19:09

answered Nov 05 '13 at 18:24

Simulant

19,190
8
63
98

Looks great, but Where you got never got an Integer I need to call again input, so many times as needed to user insert correct data. – Edgars Nov 05 '13 at 18:31
put your scanner in an other while loop repeating until your get your correct Integer. – Simulant Nov 05 '13 at 19:10

score 0 · Answer 4 · answered Nov 04 '18 at 14:45

You can request and validate user input as many times as need to do it right.

    private int readUserInput(String messageToUser) {
    System.out.print("Enter " + messageToUser);
    Scanner scan = new Scanner(System.in);
    boolean validInput = false;
    int res = 0;
    do {
      try {
        validInput = scan.hasNextInt();
        if (!validInput) {
          throw new NotIntUserInputException();
        }
        res = scan.nextInt();
        if (res < 1) {
          validInput = false;
          throw new NotPositiveIntUserInputException();
        }
      } catch (Exception e) {
        System.out.print(e.getMessage());
        scan.next();
      }
    } while (!validInput);
    return res;
  }

You have to create 2 classes NotIntUserInputException and NotPositiveIntUserInputException that are inheriting Exception class

Checking if the input value is integer type java

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