Java: run executable program whit particular parameters

Question

I need to run executable progam (.exe) in java. This program have two different operating modes: GUI and Command line. The syntax to launch the program from the command line is as follows : C:\Users\Ermanno\Desktop\ "programFolder"\"program.exe" /stext output.txt

in this way the program store the outoput in the file "output.txt".

I tired it:

Process p = new ProcessBuilder("C:\\Users\\Ermanno\\Desktop\\programFolder\\program.exe" ,"/stext a.txt").start();

does not create the output file.

I also tired to use a file batch that contains the command and run it to java but the result is the same.

"it does not work" - everytime you write this here on SO without further explanation, you should loose a finger. — Ingo, Nov 06 '13 at 10:23
From now on, never use "does not work" again. It's an insult to your intelligence and it wastes everybody's time. Instead say what you expect to happen and what happened instead. — Aaron Digulla, Nov 06 '13 at 10:45

Aaron Digulla · Answer 1 · 2013-11-06T11:00:07.167

2

You need to pass each argument in a single string:

... program.exe", "/stext", "a.txt")...

Also make sure that you start a background thread which reads the output of the child process. If there is a problem, then the child will print an error message to it's standard output and if you don't actively read it, then this output will be lost.

For this, loop over the streams p.getInputStream() and p.getErrorStream().

The latter is especially important since you say "I also tired to use a file batch". Java doesn't do anything different than a batch script. If you can't run the command from batch, it won't work from Java, either.

edited Nov 06 '13 at 11:00

answered Nov 06 '13 at 10:19

Aaron Digulla

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maybe the problem is windows 8? – ermanno.tedeschi Nov 06 '13 at 10:49
No. Do you read and print the standard output of the process? – Aaron Digulla Nov 06 '13 at 10:52
System.out.println(p.waitFor()); this as output from 0. If I run your command start the gui. – ermanno.tedeschi Nov 06 '13 at 10:56
Can you post the code? If I print p.getInputStream() and p.getErrorStream() the output is this: java.io.BufferedInputStream@5636bc0a java.io.BufferedOutputStream@237360be – ermanno.tedeschi Nov 06 '13 at 11:02
Use code similar to [IOUtils.copyLarge](http://grepcode.com/file/repo1.maven.org/maven2/commons-io/commons-io/1.4/org/apache/commons/io/IOUtils.java#IOUtils.copyLarge%28java.io.InputStream%2Cjava.io.OutputStream%29). – Aaron Digulla Nov 06 '13 at 11:29
Use one of the streams as input and `System.out` as output. – Aaron Digulla Nov 06 '13 at 11:29
The stram autput is empty – ermanno.tedeschi Nov 06 '13 at 11:45
Yes if I run command to command line the output file is generated – ermanno.tedeschi Nov 06 '13 at 14:53

score 1 · Answer 2 · answered Nov 06 '13 at 11:01

My experience was horrible with using the JDK ProcessBuilder and Runtime.getRuntime().exec. I then moved to Apache commons-exec. Here is an example:

String line = "AcroRd32.exe /p /h " + file.getAbsolutePath();
CommandLine cmdLine = CommandLine.parse(line);
DefaultExecutor executor = new DefaultExecutor();
int exitValue = executor.execute(cmdLine);

score 0 · Accepted Answer · answered Nov 07 '13 at 08:13

0

I solved using file bath. This file contains the command.

String [] _s = {"cmd.exe", "/c", "start", "file.bat"}; Process pr = Runtime.getRuntime().exec(_s);

answered Nov 07 '13 at 08:13

ermanno.tedeschi

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Java: run executable program whit particular parameters

3 Answers3