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I'm relatively new to programming and taking a course in C++ currently. I haven't had any major problems so far. I am making a program where an X amount judges can score 0.0 - 10.0 (double) and then the highest and lowest one is removed then an average is calculated and printed out.

This part is done, now I want to read from a file in the shape of: example.txt - 10.0 9.5 6.4 3.4 7.5

But I am stumbling onto problems with the dot (.) and how to get around it to get the number into a double. Any suggestions and (good) explanations so I can understand it?

TL;DR: Reading from file (E.G. '9.7') to a double variable to put into an array.

gsamaras
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Danieboy
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2 Answers2

7

Since your textfile is whitespace delimited, you can use that to your advantage by utilizing std::istream objects who skip whitespace by default (in this case, std::fstream):

#include <fstream>
#include <vector>
#include <cstdlib>
#include <iostream>

int main() {
    std::ifstream ifile("example.txt", std::ios::in);
    std::vector<double> scores;

    //check to see that the file was opened correctly:
    if (!ifile.is_open()) {
        std::cerr << "There was a problem opening the input file!\n";
        exit(1);//exit or do additional error checking
    }

    double num = 0.0;
    //keep storing values from the text file so long as data exists:
    while (ifile >> num) {
        scores.push_back(num);
    }

    //verify that the scores were stored correctly:
    for (int i = 0; i < scores.size(); ++i) {
        std::cout << scores[i] << std::endl;
    }

    return 0;
}

Note:

It is highly recommended to use vectors in lieu of dynamic arrays where possible for a myriad number of reasons as discussed here:

When to use vectors and when to use arrays in C++?

Community
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jrd1
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1

Try this:

#include <iostream>
#include <fstream>

int main() 
{
    std::ifstream fin("num.txt");
    double d;
    fin >> d;
    std::cout << d << std::endl;
}

Does that do what you want?

kmort
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  • Your version only reads *one* double number. And, it is stored in a *variable* and *not* an array (as the OP stated). – jrd1 Nov 10 '13 at 09:29
  • @jrd1 concur with both things you mentioned, but the point was to help with the main concept he was struggling with, which I interpreted as reading in doubles because of the decimal point. I find there is nothing quite like experience when learning. If I'm given too much right off the bat, I tend to not learn as deeply. Oh well. YMMV. :-) – kmort Nov 10 '13 at 14:11