Finding the Index of a character within a string

Question

This may be worded incorrectly because I'm a wee beginner, but if I have a string how to I find a certain characters index like you can with the .index thing in lists.

With a list it makes sense:

 l = ["cat", "dog", "mouse"]

 animal = l.index["dog"]

will return [1], but how do I do the same thing with strings . . .

 s = "mouse"

 animal_letter = s.index["s"]

it says there is no attribute .index

Is there another way I can do this?

`animal_letter = s.index("s")` don't used brackets. `l.index["dog"]` does not work either. — dansalmo, Nov 10 '13 at 19:54
Can't find a definitive answer to this, is there a difference between my method and yours? s.find vs s.index? — Will P, Nov 11 '13 at 22:34

score 4 · Accepted Answer · edited Nov 10 '13 at 19:58

4

Try the string.find method.

s = "mouse"
animal_letter = s.find('s')
print animal_letter

It returns the 0-based index (0 is the first character of the string) or -1 if the pattern is not found.

>>> "hello".find('h')
0
>>> "hello".find('o')
4
>>> "hello".find("darkside")
-1

edited Nov 10 '13 at 19:58

kfsone

23,617
2
42
74

answered Nov 10 '13 at 19:53

Will P

192
1
9

Does this work in scenarios like "hello".find('l') . I think it will return first l letter in the string. – emkarachchi Feb 15 '20 at 13:38
https://stackoverflow.com/a/11122355/7704650 hope this will work in those kind of scenarios. – emkarachchi Feb 15 '20 at 14:10

Finding the Index of a character within a string

1 Answers1

Linked