Time offset in python2.7

Question

I'm trying to shift a time forward or backward depending on some integer value. So far, I've been just adding (or subtracting) that time shift from the hour then using mod 24 when I create the time

time_structure = datetime.time((hour + time_zone_shift)%24, minute, second)

This works for the most part (except with rolling back the date, i.e if the time given is 7:30 and then the time_zone_shift is -8). I was wondering if there is a more "pythonic" way to do this?

Possible duplicate: http://stackoverflow.com/questions/100210/python-easy-way-to-add-n-seconds-to-a-datetime-time — Pedro Werneck, Nov 11 '13 at 00:12
You might want to take a look at the pytz module: http://pytz.sourceforge.net/ — Asad Saeeduddin, Nov 11 '13 at 00:12
By the way, you shouldn't be doing this for time zone changes. There are ways to create timezone aware datetime objects. — Pedro Werneck, Nov 11 '13 at 00:13

score 0 · Answer 1 · answered Nov 11 '13 at 00:47

So to answer your question, you should use datetime.timedelta to offset a time:

time_structure = (datetime.datetime(0, 0, 0, hour, minute, second) + datetime.timedelta(hours=time_zone_shift)).time()

But as expressed in the comments, you should really use pytz for time zone math since it can be rather complicated.

Time offset in python2.7

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