I need to check a JavaScript array to see if there are any duplicate values.

Question

I have an array

var a =["color", "radius", "y", "x", "x", "x"];

How to check, that this array does not have the same elements?

By "not have the same elements", do you mean you want to check if there are no duplicates? — bilalq, Nov 11 '13 at 08:08
but this has same elements. Try to define your question bit more. — Jai, Nov 11 '13 at 08:12

score 0 · Accepted Answer · answered Nov 11 '13 at 08:11

Try this,

var a = ["color", "radius", "y", "x", "x", "x"];
var uniqueval = a.filter(function (itm, i, a) {// array of unique elements
    return i == a.indexOf(itm);
});
if (a.length > uniqueval.length) {
    alert("duplicate elements")
}
else{
    alert('Unique elements')
}

Demos with duplicate and unique elements

Ricky Stam · Answer 2 · 2013-11-11T08:20:23.863

0

If the newArray has elements inside it then you have dublicates. You can then remove the elements of newArray from the original Array.

var a = ["color", "radius", "y", "x", "x", "x"];
var sortA = a.sort();
var newArray = [];
for (var i = 0; i < a.length - 1; i++) {
    if (sortA[i + 1] == sortA[i]) {
        newArray.push(sortA[i]);
    }
}

alert(newArray);

edited Nov 11 '13 at 08:20

answered Nov 11 '13 at 08:13

Ricky Stam

2,116
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If it helped you please accept it as answered or vote it up plz. – Ricky Stam Nov 11 '13 at 09:18

score 0 · Answer 3 · answered Jul 17 '14 at 15:26

0

This is super simple:

var i, a = ["color", "radius", "y", "x", "x", "x"];

for (i = 0; i < a.length; ++i) {
    if(a.indexOf(a[i]) != a.lastIndexOf(a[i]))
          alert("Duplicate found!");
}

Fiddle here

answered Jul 17 '14 at 15:26

prograhammer

20,132
13
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118

I need to check a JavaScript array to see if there are any duplicate values.

3 Answers3

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