How to restart a Java Application launching a specific class of my application?

Question

I have the following situatation:

I have a Java Swing application.

In the class that implement my GUI I have a button named Log Out tath is binding to an event listener that handle the click event, something like it:

JButton logOutButton = new JButton("LogOut");
header.add(logOutButton);

Then in the same class that implement my GUI I have declared the ActionListener that handle this event using an inner class:

    logOutButton.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent event) {
            System.out.println("logOutButton clicked !!!");
            System.exit(0);
        }
    });

In this moment when I click the logOutButton button the program end. I would that instead exit it is restarted by running a specific class called LoginForm (the class that implement the login form GUI)

What can I do to do this thing?

Tnx

Andrea

I think that I need to restart my application to lost some settings — AndreaNobili, Nov 11 '13 at 16:43
I think you should reorder your code and call something like a reset method to place your application back into a virgin state. — Paul Whelan, Nov 11 '13 at 16:46
1st) Remove System.exit() 2nd) Go Back to LoginForm :) create a new instance or make a resetButton — nachokk, Nov 11 '13 at 17:14

score 1 · Answer 1 · edited May 23 '17 at 12:19

You don't really need to close/open window junky approach at all. Just use Card Layout:

set Frame's content pane's layout to card layout.
```
getContentPane().setLayout(new CardLayout());
```
Put your different Form's content code inside different panel and add them to the content pane with their corresponding name, for example:
```
 getContetnPane().add(logInFormPanel, "logIn Form");
```

Now you can simulate the card to appear whenever necessary by calling CardLayout.show(Container parent, String name). For example:

 logOutButton.addActionListener(new ActionListener() {
         public void actionPerformed(ActionEvent event) {
              System.out.println("logOutButton clicked !!!");
          CardLayout cl = (CardLayout)(getContentPane().getLayout());
          cl.show(getContentPane(), "logIn Form");

    }
});

Check out a CardLayout demo from my another answer.

How to restart a Java Application launching a specific class of my application?

1 Answers1

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