Error with django-geoposition/json-response

Question

I'm doing an autocomplete input.

I'm trying to create a json response. In my model I have this:

   position = GeopositionField(default=DEFAULT)

When I try to create the json response gives me this error:

   TypeError: Geoposition(40,2) is not JSON serializable

How could I fix this ?

Edit 1:

In views.py:

data =[{'label': n.nombre, 'nombre': n.nombre, 'posicion': n.position, 'status': n.estado} for n in
               Dispositivo.objects.filter(nombre__icontains=what)]

return HttpResponse(json.dumps(data), mimetype='application/json')

How are you creating the response? – che Nov 11 '13 at 16:57 — che, Nov 11 '13 at 16:57
@che I edit the question. Look now – Don Nov 11 '13 at 17:02 — Don, Nov 11 '13 at 17:02

score 4 · Accepted Answer · answered Nov 11 '13 at 19:16

4

The problem is pretty much the what the exception says. GeopositionField is a complex type, which does not have any standard way of serializing to JSON. You have to split it up into individual coordinates, for example by convertion it to a dictionary in your model.

Like this:

class Dispositivo(models.Model):
    ...

    def position_dict(self):
        return {'lat': self.position.latitude, 'lon': self.position.longitude}

And then in data you're dumping, write {... 'position': n.position_dict(), ...} to use the dictionary representation instead of the complex field.

answered Nov 11 '13 at 19:16

che

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Thanks for helping. Now, how can I serialize a decimal?I tried `Decimal(n.position.latitude)` in data and didn't work.I could to serialize converting to a string `str(n.position.latitude)` – Don Nov 12 '13 at 08:50
How can I use `position_dict` in a query like that: `a=Dispositivo.objects.filter(bla='bla').values(...,position_dict.lat,position_dict.lon)` – Don Nov 12 '13 at 12:46
@Don: I don't think you can. – che Nov 12 '13 at 19:58

Robson Alves · Answer 2 · 2018-09-25T03:07:39.267

1

I solved this problem just by putting CharField when serializer on GeopositionField

on serializers.py put this:

position = serializers.CharField(max_length=100)

edited Sep 25 '18 at 03:07

answered Sep 16 '18 at 19:14

Robson Alves

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Error with django-geoposition/json-response

2 Answers2