Batch file randomizer 1-30 then output 5 Numbers

Question

I need a batch file randomizer to randomly select 5 numbers from 1-30 then output them. I have researched and found nothing that is useful to me. I am a Beginner so if you could make the code simple and explain it so i can reproduce it later if i need it again.

score 3 · Answer 1 · answered Nov 12 '13 at 07:20

batch noob answer is absolutly correct, but can generate duplicated numbers. For an option with no duplicate numbers,

@echo off

    setlocal enableextensions

    for /F "tokens=2" %%l in ('cmd /v:on /c "@for /L %%n in (1 1 30) do @echo ^!random^! %%n"^|sort^|more +25') do (
        echo %%l
    )

It spawns a cmd (cmd /v:on /c "....") to generate a list of numbers 1-30 prefixed with a random number, this list is then sorted (sort), using the random number as key. Once sorted, more +25 is used to skip the first 25 numbers in list, and then, a for /F is used to step over the 5 last lines, taking the second token from it (the lines contains the random number and the number from 1-30) and echoing it to console

+1, Good idea, but your script will give the exact same sequence if run multiple times within 1 second because of the [random number seed issue](http://stackoverflow.com/a/19694573/1012053) when CMD.EXE is launched. Better to write the list of random numbers to a file without launching new CMD.EXE, and then read the file with FOR /F. — dbenham, Nov 13 '13 at 00:38

score 1 · Accepted Answer · edited Dec 23 '15 at 02:49

1

Use RANDOM -- that's what you are looking for.

RANDOM gives a number between 0 and 32767.

Example:

set /a num=%random% 
echo.%num%

This will output a number between 0 and 32767.

But if you want to reduce that number do this:

set /a num=%random% %%5
echo.%num%

This will output a number between 0 and 4.

In your case (range 1 to 30) do this:

set /a num1=%random% %%30 +1
set /a num2=%random% %%30 +1
set /a num3=%random% %%30 +1
set /a num4=%random% %%30 +1
set /a num5=%random% %%30 +1

echo %num1%
echo %num2%
echo %num3%
echo %num4%
echo %num5%

Hope it helps! :D

edited Dec 23 '15 at 02:49

aschipfl

33,626
12
54
99

answered Nov 12 '13 at 04:57

QbicSquid

165
1
5

2

with `set /a num=%random% %5` you will get output between 0 and **4**. add one to get output between 1 and 5 – Stephan Nov 12 '13 at 06:08
:| ok thnx for telling – QbicSquid Nov 21 '13 at 10:11
`%RANDOM%` will return numbers from `0` to **`32767`**! – aschipfl Dec 23 '15 at 02:45

Batch file randomizer 1-30 then output 5 Numbers

2 Answers2