Feed line number to sed

Question

I have a piped unix script which finally yields a line number to me in the subject file.
Now,I need to print out the file contents from this particular line to the end.
Is it possible to feed the line number to sed via xargs,for sed to print out the desired.

.....|tail -1 | cut -f 1 | xargs sed ...?

Is this possible?

There's probably a way to do this, but are you sure it wouldn't be easier to enclose the whole thing in backticks? sed -n "`.....|tail -1 | cut -f 1`p" filename — Beta, Nov 12 '13 at 06:42
@Beta Backtics should not be use, use parentheses `$(code)` http://stackoverflow.com/questions/4708549/shell-programming-whats-the-difference-between-command-and-command — Jotne, Nov 12 '13 at 06:57

pobrelkey · Accepted Answer · 2013-11-12T07:42:01.797

0

..... | tail -1 | cut -f 1 | xargs -i sed -n '{},$p' your_file

edited Nov 12 '13 at 07:42

answered Nov 12 '13 at 07:24

pobrelkey

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Doesnt work - just prints the line itself - rather than to the end of the file – IUnknown Nov 12 '13 at 07:40
Sorry, I missed that in the OP. Edited to add this. – pobrelkey Nov 12 '13 at 07:42

Feed line number to sed

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