How can I make character "[" and "]" as the pattern in RegExp() function?

Question

As the title above, I want to know how to make these two characters be a pattern in RegExp() function in javascript.
I have tried to put a backlash before it. It works for another special chars, but not for these two.
This is my current pattern :

var disallowed_char=new RegExp("[~!@#$%\^&*()\{\}\\\|\'\"\;\:\.\,\>\<\=\_\+\`\?\/\-]");
// It works

I want char [ and ] be a part of the pattern, so I add these to the pattern :

var disallowed_char=new RegExp("[~!@#$%\^&*()\{\}\\\|\'\"\;\:\.\,\>\<\=\_\+\`\?\/\[\]\-]");
//I put it before - (minus) char, 
//because minus char won't work if placed at the first or in the middle of the pattern
//note : I have tried to put "[" and "]" in other place
//but still doesn't work

Is there any way to make it as I want?

[Here are some useful resources](http://google.com/#q=use+square+brackets+regex). — Qantas 94 Heavy, Nov 13 '13 at 01:58
http://stackoverflow.com/questions/928072/whats-the-regular-expression-that-matches-a-square-bracket — Nico, Nov 13 '13 at 01:58
Why are you using `var reg = new Regexp("string")` instead of `var reg = /literal/` where you don't need to escape ` \ ` ? — some, Nov 13 '13 at 02:01

score 2 · Accepted Answer · answered Nov 13 '13 at 02:03

2

There are two ways to declare a JavaScript regex:

var disallowed_char=/\[/;
var disallowed_char=new RegExp("\\[");

When you use the second notation, you need to double escape the backslash because it is already an escape character in JavaScript strings.

answered Nov 13 '13 at 02:03

Christophe

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How can I make character "[" and "]" as the pattern in RegExp() function?

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