I have a method like this:
public function xy()
{
die('script was terminated.')
}
If it possible to test this method with phpUnit?
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John Conde
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user2988390
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Probably not (easily). PHPUnit will not be able to distinguish that method's `die()` from a real `die()`, and will, well, just `die()`. – Michael Berkowski Nov 13 '13 at 15:47
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Instead you would need to wrap the `die()` in some other function that takes a different action if run inside a test. – Michael Berkowski Nov 13 '13 at 15:47
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If your function "xy" just do a die(), then I would simply create a mock and then I would assert if that function was called. – Guillermo Mansilla Nov 13 '13 at 16:37
1 Answers
2
This is possible by overloading the die() function. How you do this is described here: Intercepting the Exit Statement
Simply calling it is not possible as there is only one PHPUnit process and you will kill it by calling die() or exit().
Also have look at the answers to this question: How do you use PHPUnit to test a function if that function is supposed to kill PHP?
