Calling PHP file with AJAX

Question

I have a php file that takes a array and an integer and returns a string. I would like to get that string, however, when I log the result to the console, I see an object and don't see my string anywhere inside

result = $.ajax({ url: 'myPhpFile.php?firstargument=myArray&secondargument=myInteger' });

console.log(result);

that's because you aren't waiting for the ajax to complete. Use the success/done callback. — Kevin B, Nov 13 '13 at 19:23
oh i see, but i'm getting a result back each time so i'm assuming its completing? — LemonMan, Nov 13 '13 at 19:25
Nope. result will always be an object regardless of the outcome. That object is known as the jqXHR. — Kevin B, Nov 13 '13 at 19:26

score 1 · Accepted Answer · answered Nov 13 '13 at 19:29

1

You can try to next script:

$.ajax({
   type: "GET",
   url: "myPhpFile.php",
   data: { firstargument: myArray, secondargument: myInteger }
})
.done(function(result){
   console.log(result);
});

answered Nov 13 '13 at 19:29

fortegente

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this worked great, thank you! is there a reason you used get rather than post? – LemonMan Nov 13 '13 at 20:35

Calling PHP file with AJAX

1 Answers1