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I was reading a tutorial on Javascript basics & how it is different from other languages like C, C++ in terms of having function-level scope rather than block-level scope, but, came across this script which got me confused!

So, Basically:

  1. I want to know how does outcome of the following code comes to be '1'?

  2. And exactly what is the role of function a() {} ? I mean its never called and in function b() {} also there's a return statement before its declaration. But if i change the function name , the alert gives the value '10'.Why?

    <script>
    var a = 1;

    function b() {  
        a = 10;
        return;
        function a() {}
    }

    b();
    alert(a);
</script>
Joren
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n4m31ess_c0d3r
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  • @Sarath I have still one doubt remaining why the functional decalaration " function a() {} " is being parsed into functional expressions "var a= function a() {} " – n4m31ess_c0d3r Nov 14 '13 at 14:02
  • The difference is that `var a= function() {}` is defined at run-time, whereas `function a() {}` is defined at parse-time ., http://stackoverflow.com/questions/336859/var-functionname-function-vs-function-functionname – Sarath Nov 14 '13 at 14:07

0 Answers0