Python: for loop - print on the same line

Question

I have a question about printing on the same line using for loop in Python 3. I searched for the answer but I couldn't find any relevant.

So, I have something like this:

def function(s):
    return s + 't'

item = input('Enter a sentence: ')

while item != '':
    split = item.split()
    for word in split:
        new_item = function(word)
        print(new_item)
    item = input('Enter a sentence: ')

When a user types in 'A short sentence', the function should do something with it and it should be printed on the same line. Let's say that function adds 't' to the end of each word, so the output should be

At shortt sentencet

However, at the moment the output is:

At
shortt
sentencet

How can I print the result on the same line easily? Or should I make a new string so

new_string = ''
new_string = new_string + new_item

and it is iterated and at the end I print new_string?

thefourtheye · Accepted Answer · 2013-11-17T14:25:58.560

25

Use end parameter in the print function

print(new_item, end=" ")

There is another way to do this, using comprehension and join.

print (" ".join([function(word) for word in split]))

edited Nov 17 '13 at 14:25

answered Nov 17 '13 at 14:19

thefourtheye

233,700
52
457
497

score 9 · Answer 2 · edited Mar 05 '20 at 15:11

9

The simplest solution is using a comma in your print statement:

>>> for i in range(5):
...   print i,
...
0 1 2 3 4

Note that there's no trailing newline; print without arguments after the loop would add it.

edited Mar 05 '20 at 15:11

wjandrea

28,235
9
60
81

answered Aug 21 '15 at 09:30

Mohsin Khazi

91
1
1

Note this only works in Python 2, and OP seems to be using Python 3 – wjandrea Mar 05 '20 at 15:14

Ashwini Chaudhary · Answer 3 · 2013-11-17T14:33:31.933

2

As print is a function in Python3, you can reduce your code to:

while item:
    split = item.split()
    print(*map(function, split), sep=' ')
    item = input('Enter a sentence: ')

Demo:

$ python3 so.py
Enter a sentence: a foo bar
at foot bart

Even better using iter and partial:

from functools import partial
f = partial(input, 'Enter a sentence: ')

for item in iter(f, ''):
    split = item.split()
    print(*map(function, split), sep=' ')

Demo:

$ python3 so.py
Enter a sentence: a foo bar
at foot bart
Enter a sentence: a b c
at bt ct
Enter a sentence: 
$

edited Nov 17 '13 at 14:33

answered Nov 17 '13 at 14:27

Ashwini Chaudhary

244,495
58
464
504

1

I always had this doubt, can we use `iter` to stop when any of the items in a list is encountered? – thefourtheye Nov 17 '13 at 14:39
1

@thefourtheye I don't think so, because we don't have access to `item` inside `iter`, but we can use `itertools.takewhile` for that. – Ashwini Chaudhary Nov 17 '13 at 14:45
@hcwhsa You mean we can combine `iter` and `takewhile` to do that? – thefourtheye Nov 17 '13 at 14:54
1

Downvoter, could you please explain why? – thefourtheye Nov 17 '13 at 14:54
1

@thefourtheye No, just `takewhile`: `for x in takewhile(lambda x: x not in my_list, (x() for x in repeat(f)))`, where `f` is `f = partial(input, 'Enter a sentence: ')` – Ashwini Chaudhary Nov 17 '13 at 15:33

Python: for loop - print on the same line

3 Answers3

Linked

Related