Number is too large Exception in Java

Question

I am trying to print this integer number

 int a=07;
System.out.println("Value of a is "+a);

it runs and shows value of a is 7 but when i change the value of a

 int a=08;
System.out.println("Value of a is "+a);

then it shows integer number too large

I dont know why... Can any body tell me ?

Bad exception message from JVM IMHO as int b=a; won't even compile. — Alex, Nov 18 '13 at 12:03

score 8 · Accepted Answer · answered Nov 18 '13 at 11:59

8

It's beause the JVM interprets this number as octal, and there's no symbol 8 in octal.

Any number starting by 0 is an octal number.

answered Nov 18 '13 at 11:59

Oscar Pérez

i understand it but if 0 to 7 are octal numbers then 07*07 why its answer is 49 ? – Engineer Nov 18 '13 at 12:02
1

Because the result is expressed in decimal. `07` in octal is exactly the same as `7 ` in decimal. `07 x 07 = 061` and `061=47` – Oscar Pérez Nov 18 '13 at 12:05
you are saying that 061=47 but answer is 49 not 47? – Engineer Nov 18 '13 at 12:08
Excuseme, that was a typo, I should have said: `061=49` – Oscar Pérez Nov 18 '13 at 12:11
In java if i am multiplying two octal numbers then how i will get its result in octal? – Engineer Nov 18 '13 at 12:15
I any language, numbers are numbers. If you want to represent ANY number in other system, you must tell so to the outputing libraries. In the particular case of java, you can use: `Integer.toOctalString( 49 )` – Oscar Pérez Nov 18 '13 at 12:18
1

Glad to have helped you – Oscar Pérez Nov 18 '13 at 12:28

score 0 · Answer 2 · answered Nov 18 '13 at 11:59

0

08 is octal 8 which is not valid since octal numbers are only from 0 to 7.

You should try:

int a=8;
System.out.println("Value of a is "+a);

answered Nov 18 '13 at 11:59

Adam Arold

2 Answers2