How can I check if a file is mp3 or image file?

Question

How can I check if a file is an mp3 file or image file, other than check each possible extension?

Answer 1

Native ways to get the mimetype:

For PHP < 5.3 use mime_content_type()
For PHP >= 5.3 use finfo_fopen()

Alternatives to get the MimeType are exif_imagetype and getimagesize, but these rely on having the appropriate libs installed. In addition, they will likely just return image mimetypes, instead of the whole list given in magic.mime.

If you don't want to bother about what is available on your system, just wrap all four functions into a proxy method that delegates the function call to whatever is available, e.g.

function getMimeType($filename)
{
    $mimetype = false;
    if(function_exists('finfo_fopen')) {
        // open with FileInfo
    } elseif(function_exists('getimagesize')) {
        // open with GD
    } elseif(function_exists('exif_imagetype')) {
       // open with EXIF
    } elseif(function_exists('mime_content_type')) {
       $mimetype = mime_content_type($filename);
    }
    return $mimetype;
}

Answer 2

You can identify image files using getimagesize.

To find out more about MP3 and other audio/video files, I have been recommended php-mp4info getID3().

Answer 3

To find the mime type of a file I use the following wrapper function:

function Mime($path)
{
    $result = false;

    if (is_file($path) === true)
    {
        if (function_exists('finfo_open') === true)
        {
            $finfo = finfo_open(FILEINFO_MIME_TYPE);

            if (is_resource($finfo) === true)
            {
                $result = finfo_file($finfo, $path);
            }

            finfo_close($finfo);
        }

        else if (function_exists('mime_content_type') === true)
        {
            $result = preg_replace('~^(.+);.*$~', '$1', mime_content_type($path));
        }

        else if (function_exists('exif_imagetype') === true)
        {
            $result = image_type_to_mime_type(exif_imagetype($path));
        }
    }

    return $result;
}

Answer 4

try mime_content_type()

<?php
echo mime_content_type('php.gif') . "\n";
echo mime_content_type('test.php');
?> 

Output:

image/gif

text/plain

Or better use finfo_file() the other way is deprecated.

Answer 5

getimageinfo is best to find images . Check if return type is false .

Answer 6

You can use FileInfo module which is built into PHP since 5.3. If you are using a PHP version less than PHP 5.3, you can install it as a PECL extension:

After installation the finfo_file function will return file information.

PECL extension: http://pecl.php.net/package/fileinfo

PHP Documentation: http://www.php.net/manual/en/book.fileinfo.php

Answer 7

You could use finfo like this:

$mime = finfo_open(FILEINFO_MIME, $path_to_mime_magic_file);
if ($mime ===FALSE) {
    throw new Exception ('Finfo could not be run');
}
$filetype = finfo_file($mime, $filename);
finfo_close($mime);

or if you have problems with finfo not being installed, or the mime magic file just not working (it works correctly on 3 out of our 4 servers - all identical OS and PHP installs) - then try using Linux's native file (don't forget to sanitise the filename though: in this example, I know the filename can be trusted as it's a PHP temporary filename in my test code):

ob_start();
system('file -i -b '.$filename);
$output = ob_get_clean();
$output = explode("; ", $output);
if (is_array($output)) {
     $filetype = trim($output[0]);
}

Then just pass the mime file type to a switch statement like:

switch (strtolower($filetype)) {
            case 'image/gif':
                return '.gif';
                break;
            case 'image/png':
                return '.png';
                break;
            case 'image/jpeg':
                return '.jpg';
                break;
            case 'audio/mpeg':
                return '.mp3';
                break;
}
return null;

Answer 8

This function checks if the file is an image based on extension and mime and returns true if it's a browser compatible image...

function checkImage($image) {

//checks if the file is a browser compatible image

$mimes = array('image/gif','image/jpeg','image/pjpeg','image/png');
//get mime type
$mime = getimagesize($image);
$mime = $mime['mime'];

$extensions = array('jpg','png','gif','jpeg');
$extension = strtolower( pathinfo( $image, PATHINFO_EXTENSION ) );

if ( in_array( $extension , $extensions ) AND in_array( $mime, $mimes ) ) return TRUE; 
else return FALSE; 

}

Answer 9

For Images, I use:

    function is_image($path)
   {
    $a = getimagesize($path);
    $image_type = $a[2];

    if(in_array($image_type , array(IMAGETYPE_GIF , IMAGETYPE_JPEG ,IMAGETYPE_PNG , IMAGETYPE_BMP)))
    {
        return true;
    }
    return false;
    }

Answer 10

The best way is to use finfo_file function. Example:

<?php 
if (isset($_FILES['yourfilename']['tmp_name'])) {
    $finfo = finfo_open(FILEINFO_MIME_TYPE);
    $mime = finfo_file($finfo, $_FILES['yourfilename']['tmp_name']);
    if ($mime == 'image/jpg') {
        echo "It's an jpg image!";
    }
    finfo_close($finfo);
}
?>

Answer 11

This function get a file path and with use finfo_open and mime_content_type if supported, return image or video or audio string.

/**
 * get file type
 * @return image, video, audio
 */
public static function getFileType($file)
{
    if (function_exists('finfo_open')) {
        if ($info = finfo_open(defined('FILEINFO_MIME_TYPE') ? FILEINFO_MIME_TYPE : FILEINFO_MIME)) {
            $mimeType = finfo_file($info, $file);
        }
    } elseif (function_exists('mime_content_type')) {
        $mimeType = mime_content_type($file);
    }
    if (strstr($mimeType, 'image/')) {
        return 'image';
    } else if (strstr($mimeType, 'video/')) {
        return 'video';
    } else if (strstr($mimeType, 'audio/')) {
        return 'audio';
    } else {
        return null;
    }
}