PHP splitting array into two arrays based on value

Question

I have a PHP array that I am trying to split into 2 different arrays. I am trying to pull out any values that contain the word "hidden". So one array would contain all the values that do not contain the word "hidden". The other array would contain all the values that do contain the word "hidden". I just can't figure out how to do it though.

The original array is coming from a form post that contains keys and values from a bunch of check boxes and hidden inputs. so the actual post value looks something like this:

Group1 => Array([0] => item1,[1] => item2hidden,[2] => item3,[3] => item4,[4] => item5hidden)

so to simplify it:

$myArray = Array(item1, item2hidden, item3, item4, item5hidden)

final output

$arr1 = (item1, item3, item4)
$arr2 = (item2hidden, item5hidden)

Anyone know how to do something like this?

score 30 · Answer 1 · edited Apr 07 '22 at 00:31

30

You can use array_filter() function:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');

$arr1 = array_filter($myArray, function($v) { return strpos($v, 'hidden') === false; });
$arr2 = array_diff($myArray, $arr1);

edited Apr 07 '22 at 00:31

Giacomo1968

25,759
11
71
103

answered Nov 20 '13 at 14:18

Glavić

42,781
13
77
107

Need to be `=== false;` instead of `== false;` – Narek Nov 20 '13 at 14:24
Doesn't work if you have array values inside your initial array. For instance, $myArray = [['id' => 1], ['id'] => 2]; – andnik Jul 22 '19 at 16:15
@andnik: just replace `strpos($v, ...`to `strpos($v['id'], ...` – Glavić Jul 24 '19 at 14:47
@Glavić, thanks, but I'm referring to second part. array_diff doesn't work when you are using multidimensional array. This link seems to contain answer I was looking for: https://stackoverflow.com/questions/11821680/array-diff-with-multidimensional-arrays – andnik Jul 24 '19 at 15:30

score 10 · Accepted Answer · answered Nov 20 '13 at 14:17

This should do the trick:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$secondaryArray = array();

foreach ($myArray as $key => $value) {
    if (strpos($value, "hidden") !== false) {
        $secondaryArray[] = $value;
        unset($myArray[$key]);
    }
}

It moves all the entries that contain "hidden" from the $myArray to $secondaryArray.

Note: It's case sensitive

score 0 · Answer 3 · answered Nov 20 '13 at 14:18

$myArray = Array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$arr1 = array();
$arr2 = array();    
foreach ($myArray as $item) {
    if (strpos($item, "hidden") !== false) {
        $arr1[] = $item;
    } else {
        $arr2[] = $item;
    }
}

This solution checks if 'hidden' present at current item, if no, move to $arr1 else to $arr2

score 0 · Answer 4 · answered Nov 20 '13 at 14:24

You can use array_filter:

function filtreHiddens($e) {
    if (isset($e['hidden']) && $e['hidden']) return true;
    else return false;
}

function filtreNotHiddens($e) {
    if (isset($e['hidden']) && !$e['hidden']) return true;
    else return false;
}

$arrayToFiltre = array(
    array('hidden' => true, 'someKey' => 'someVal'),
    array('hidden' => false, 'someKey1' => 'someVal1'),
    array('hidden' => true, 'someKey2' => 'someVal3'),
);

$hidden = array_filter($arrayToFiltre, 'filtreHiddens');
$notHidden = array_filter($arrayToFiltre, 'filtreNotHiddens');

print_r($hidden);
print_r($notHidden);

score 0 · Answer 5 · answered Nov 20 '13 at 14:42

0

Maybe it's just me, but I would go for the clarity of regular expressions...

foreach($myArray as $item) {
    if (preg_match("/hidden$/i", $item)) {
        array_push($arr2, $item);
    } else {
        array_push($arr1, $item);
    }
}

answered Nov 20 '13 at 14:42

fresbeeplayer

93
1
5

PHP splitting array into two arrays based on value

5 Answers5

Linked