Php - get path after php script

Question

I have search high and low for an answer to my question and I cannot find it. Basically what I want to do is get the path after a php script. ex. "http://www.example.com/index.php/arg1/arg2/arg3/etc/" and get arg1, arg2, arg3, etc in an array. How can I do this in php and once I do this will "http://www.example.com/arg1/arg2/arg3/etc" still return the same results. If not then how can I achieve this?

Look up `$_SERVER`, `PATH_INFO` and `explode`. – cHao Nov 21 '13 at 05:27 — cHao, Nov 21 '13 at 05:27

Darren Cook · Accepted Answer · 2013-11-21T06:56:54.510

5

Here is how to get the answer, and a few others you will have in the future. Make a script, e.g. "test.php", and just put this one line in it:

<?php phpinfo();

Then browse to it with http://www.example.com/test.php/one/two/three/etc

Look through the $_SERVER values for the one that matches what you are after.

I see the answer you want in this case in $_SERVER["PATH_INFO"]: "/one/two/three/etc" Then use explode to turn it into an array:

print_r( explode('/',$_SERVER['PATH_INFO'] );

However sometimes $_SERVER["REQUEST_URI"] is going to be the one you want, especially if using URL rewriting.

UPDATE:

Responding to comment, here is what I'd do:

$args = explode('/',$_SERVER['REQUEST_URI']);
if($args[0] == 'index.php')array_shift($args);

edited Nov 21 '13 at 06:56

answered Nov 21 '13 at 05:26

Darren Cook

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Nice answer but before I accept it I need to know if it is possible to make http://www.example.org/arg1/arg2 act the same as http://www.example.org/index.php/arg1/arg2. – john01dav Nov 21 '13 at 06:01
@john01dav So the same script can be used for either way of being called? Yes, use REQUEST_URI, explode out, then filter out "index.php" if it is there. I'll update my answer. – Darren Cook Nov 21 '13 at 06:54
No, I mean actually making the script be loaded like that and not interpreted as a directory as it currently is. – john01dav Nov 21 '13 at 22:59
@john01dav That is a distinctly different question. Short answer is it is done with Apache config. E.g. see: http://stackoverflow.com/questions/5214502/how-to-redirect-all-requests-to-index-php-and-keep-the-other-get-params – Darren Cook Nov 21 '13 at 23:16

score 1 · Answer 2 · answered Nov 21 '13 at 05:39

1

Try like this :

$url ="http://www.example.com/index.php/arg1/arg2/arg3/etc/";


$array =  explode("/",parse_url($url, PHP_URL_PATH));
if (in_array('index.php', $array)) 
{
    unset($array[array_search('index.php',$array)]);
}


print_r(array_values(array_filter($array)));

answered Nov 21 '13 at 05:39

Mahmood Rehman

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I went to write something like this, then realized it will mess up this URL: example.com/arg1/index.php/arg3/ I.e. when one of the arguments is the magic string "index.php". Of course, the OP cannot do what he wants to do if index.php could validly be the first argument! – Darren Cook Nov 21 '13 at 06:58

score 0 · Answer 3 · answered Nov 21 '13 at 05:27

0

Can you try using parse_url and parse_str

$url =$_SERVER['REQUEST_URI'];

 $ParseUrl = parse_url($url);
 print_r($ParseUrl);

 $arr =  parse_str($ParseUrl['query']);

 print_r($arr);

answered Nov 21 '13 at 05:27

Krish R

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Php - get path after php script

3 Answers3