match a string using all the strings in array

Question

Hello, I'm trying to make a simple matching game in javascript.

If the the user inserts the text president goes crazy in any way that contains every strings in word_tmp, then the word_tmp becomes true, and if he misses one string then it becomes false.

word_tmp = ['president', 'goes', 'crazy'];

// string 1 contains the president, goes and crazy at one string
string1 = 'president goes very crazy'; // should output true

// string 2 doesn't contain president so its false.
string2 = 'other people goes crazy'; // should output false

How can I accomplish this?

possible duplicate of [How to check if a string array contains one string in JavaScript?](http://stackoverflow.com/questions/12623272/how-to-check-if-a-string-array-contains-one-string-in-javascript) — Damodaran, Nov 22 '13 at 07:26

score 1 · Accepted Answer · answered Nov 22 '13 at 08:22

1

Try this:

var word_tmp = ['president', 'goes', 'crazy'];
var string1 = 'president goes very crazy';

var isMatch = true;
for(var i = 0; i < word_tmp.length; i++){
    if (string1.indexOf(word_tmp[i]) == -1){
        isMatch = false;
        break;
    }
}

return isMatch //will be true in this case

answered Nov 22 '13 at 08:22

Ari

3,489
5
26
47

simplest one maybe if others need it. – Adam Ramadhan Nov 22 '13 at 08:51

Leonid Beschastny · Answer 2 · 2013-11-22T09:01:42.693

You can do it with simple reduce call:

word_tmp.reduce(function(res, pattern) {
  return res && string1.indexOf(pattern) > -1;
}, true);

The same code, wrapped in a function:

var match_all = function(str, arr) {
  return arr.reduce(function(res, pattern) {
    return res && str.indexOf(pattern) > -1;
  }, true);
};

match_all(string1, word_tmp); // true
match_all(string2, word_tmp); // false

But this solution won't work for you if you want to match whole words. I mean, it will accept strings like presidential elections goes crazy, because president is a part of the word presidential. If you want to eliminate such strings as well, you should split your original string first:

var match_all = function(str, arr) {
  var parts = str.split(/\s/); // split on whitespaces
  return arr.reduce(function(res, pattern) {
    return res && parts.indexOf(pattern) > -1;
  }, true);
};

match_all('presidential elections goes crazy', word_tmp); // false

In my example I'm splitting original string on whitespaces /\s/. If you allow punctuation marks then it's better to split on non-word characters /\W/.

score 0 · Answer 3 · answered Nov 22 '13 at 09:18

var word_tmp = ['president', 'goes', 'crazy'];
var str = "president goes very crazy"

var origninaldata = str.split(" ")
var isMatch = false;
for(var i=0;i<word_tmp.length;i++) {
   for(var j=0;j<origninaldata.length;j++) {
      if(word_tmp[i]==origninaldata[j])
        isMatch = true;
   }
}

match a string using all the strings in array

3 Answers3