what is the meaning of this line? Can any body help me? I have confusion on last 2 sign :''
why without this two sign browser make error? Thanks all.
isset($_POST['but'])? $_POST['but']:'';
what is the meaning of this line? Can any body help me? I have confusion on last 2 sign :''
why without this two sign browser make error? Thanks all.
isset($_POST['but'])? $_POST['but']:'';
U use the tenary comparison operator
A ternary operator have value for true and false
($contidition) ? true : false;
Please refer php documentation about ternary operator comparison operator
In case of:
isset( $_POST['but'] ) ? $_POST['but'] : ''
What it mean is, when $_POST['but']
exist, use it, otherwise use empty string
If u use php version > 5.3 u can use something like
isset($_POST['but']) ? : ''
If $_POST request body contains but
parameter - use it, overwise use empty string.
If you are misunderstood statement ? something : anything
code - it's the Ternary Operator
It's nothing but the Ternary Operator
Explanation:
If your $_POST['but']
is set , then it will assign the same value to it , else it will set a ''
A clear example here
Well it's called an ternary
operator.
Example:
$value = 5;
($value > 2) ? true : false; // returns true
The expression (expr1) ? (expr2) : (expr3) evaluates to expr2 if expr1 evaluates to TRUE, and expr3 if expr1 evaluates to FALSE.
(isset($_POST['but'])) ? $_POST['but']:'';
Here if your value $_POST['but']
is set then it will return $_POST['but']
else it will return ''.
It's just another way to write if/else statement. For example:
$but = isset($_POST['but'])? $_POST['but']:'';
Would be the same as:
if(isset($_POST['but'])){
$but= $_POST['but'];
}else{
$but = '';
}