Why this function return true?

Question

<?php

var_dump(in_array('ddds', array(2,3,0)));

Why this function return true? We have a string which could be converted to 1 but why to 0?

`in_array('ddds', array(2,3,0), TRUE)` returns false, properly, when you enforce strict checks. — Marc B, Nov 26 '13 at 17:29

score 4 · Answer 1 · edited May 23 '17 at 10:31

4

Because 'ddds' is equal to 0 .

edited May 23 '17 at 10:31

Community

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answered Nov 26 '13 at 17:27

Ignacio Vazquez-Abrams

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@kingkero: **Equal.** – Ignacio Vazquez-Abrams Nov 26 '13 at 17:34
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var_dump('ddds' == true) and var_dump('ddds' == 0) return true but true == 0 is false? it's strange – user2886388 Nov 26 '13 at 17:37
@user2886388: Welcome to PHP. – Ignacio Vazquez-Abrams Nov 26 '13 at 17:38

score 1 · Answer 2 · answered Nov 26 '13 at 17:31

This is because ddds == 0 is true (demo), and 0 is an element of your array. Set the strict parameter for in_array() to ensure the types are also considered.

From the documentation:

If the third parameter strict is set to TRUE then the in_array() function will also check the types of the needle in the haystack.

var_dump( in_array('ddds', array(2,3,0), TRUE) );

Output:

bool(false)

Why this function return true?

2 Answers2