Start executable with ini file in VB?

Question

Im trying to start an executable with an Ini file. We need this, so we can start lotus notes as the ini files is needed for the datapath. The shortcut is notes.exe =h:\lotus\notes\notes.ini.

I tried the following script

Set objShell = WScript.CreateObject("WScript.shell") 
objShell.run "%comspec% /c "C:\Program Files (x86)\IBM\Lotus\Notes\notes.exe"   
=h:\lotus\notes\notes.ini

Is there another way to do this?

possible duplicate of [Launch programs whose path contains spaces](http://stackoverflow.com/questions/1340355/launch-programs-whose-path-contains-spaces) — Jean-François Corbett, Mar 12 '15 at 08:14

score 1 · Accepted Answer · answered Nov 27 '13 at 10:00

%COMSPEC% is not required, but you need double quotes around the program path (because it contains spaces), and you must escape them (by prepending them with another double qoute), because they're inside a string. Without escaping you get a string "%comspec% /c " followed by an invalid "operator" C:\Program and other garbage.

Change this:

objShell.run "%comspec% /c "C:\Program Files (x86)\IBM\Lotus\Notes\notes.exe" =h:\lotus\notes\notes.ini

into this:

objShell.run """C:\Program Files (x86)\IBM\Lotus\Notes\notes.exe"" =h:\lotus\notes\notes.ini"

and the problem should disappear.

Start executable with ini file in VB?

1 Answers1