regex for mobile number validation in java

Question

I want to have phone number in working combination of '0' followed by 10 digit mobile number (or) 0091 folllowed by 10 digit mobile number (or) +91 followed by 10 digit number.

1) 0 followed and +91 folowed numbers are working with following regex i also want 0091 followed number to be worked, my regex is:

"^([0]|(?:[0][0]|\\+)(91))([7-9]{1})([0-9]{9})$";

Could you suggest me working a regex.

did you try to play around with a regexp testing site such as: http://regexpal.com/ ? — Yaneeve, Nov 27 '13 at 13:23

OGHaza · Accepted Answer · 2013-11-27T13:50:35.710

The exact regex you seem to be going for (based on what you've tried so far) is:

^(?:0091|\\+91|0)[7-9][0-9]{9}$

Begins with 0, +91 or 0091
Followed by a 7-9
Followed by exactly 9 numbers
No capture groups
Must match entire input

Working example on RegExr

As a general tip, to have worked this out yourself I'd advise using a site like RegExr or RegexPal

Set it to multi-line mode (so that ^ and $ match at the end of each line) then add 0091, +91 and 0 into the input box on separate lines - so you have something like this.

Then try to make a regex that matches just that part, in your case you needed something like

^0091|\+91|0$

Note: on RegExr you don't have to escape backslashes (so when you use the regex in java you need to go through escaping them).

score 2 · Answer 2 · answered Nov 27 '13 at 13:44

2

Guess this regex would work:

^((0091)|(\+91)|(0))([7-9]{1})([0-9]{9})$

answered Nov 27 '13 at 13:44

Vignesh

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score 1 · Answer 3 · answered Nov 27 '13 at 13:22

1

If you are working on Android, you could use this method: PhoneNumberUtils.isGlobalPhoneNumber("+91.......)

Or try to do something like that if you really want to use regex:

if (match("^0[0-9]{9}") || match("^+91[0-9]{10}") || match("^0091[0-9]{9}"))

answered Nov 27 '13 at 13:22

Manitoba

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thank u for good logic and i gave upvote – Nov 27 '13 at 13:57

Manuel Manhart · Answer 4 · 2013-11-27T13:54:14.167

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Use the following code (test.matches(..) ist the important part):

    String test = "00911234567891";
    System.out.println(test.matches("(0091|0|\\+91)[7-9][0-9]{9}"));

edited Nov 27 '13 at 13:54

answered Nov 27 '13 at 13:24

Manuel Manhart

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why / what exactly? I tried it and it returned true for 0091 + number, 0 + number and +91 + number. – Manuel Manhart Nov 27 '13 at 13:42
ah I see now the problem. You distinguish between mobile and normal number. How is a mobile number identified? – Manuel Manhart Nov 27 '13 at 13:47
sorry mate its working i upvoted ur answer – Nov 27 '13 at 13:54
@ManuelM. - the new regex is significantly worse than the previous one (which looked about right) – OGHaza Nov 27 '13 at 13:55
restored the correct version. – Manuel Manhart Nov 27 '13 at 14:01

score -1 · Answer 5 · answered Nov 27 '13 at 13:24

-1

This regex should work.

You can use ^([0]|\+91)?\d{10} as starts with 0 or +91 and 10 digits after that.

answered Nov 27 '13 at 13:24

GrIsHu

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As far as I can tell, OP doesn't want to match 2 (and in your regex exactly 2) comma separated numbers. – OGHaza Nov 27 '13 at 13:28
sorry i already have 0 and +91 working ,i need 0091 to get worked in same regex – Nov 27 '13 at 13:37

regex for mobile number validation in java

5 Answers5