Url Matching using Gruber's regex in PHP

Question

how do I get the regex mentioned in this article working with preg_match in php?

<?php
preg_match("\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))/i", $text, $matches);
print_r($matches);
?>

Using the code above I get the following error:

Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash...

Note that this regex will allow URLs like `http://./` and `http://??/`. If this is not a problem to you, you should really use `filter_var('http://www.google.com/', FILTER_VALIDATE_URL)` instead, since it’s a built-in PHP function. — Mathias Bynens, Dec 03 '10 at 13:29

score 7 · Accepted Answer · answered Jan 08 '10 at 02:36

7

Try this:

preg_match("#\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))#i", $text, $matches);

You were missing the regex delimiters (usually /, but using # here because it's more convenient for URLs)

answered Jan 08 '10 at 02:36

K Prime

1 Answers1