22

There is a way in socket.io to create a timeout in the disconnected event, then check if the user has been reconnected ?

The idea is to emit data / save user state in database only if the user is not reconnected after timeout

Edit: Followed @Are Wojciechowski answer, I'm done with a multi tabs & F5 flood handler

https://gist.github.com/foohey/7696811

m4tm4t
  • 2,361
  • 1
  • 21
  • 37

1 Answers1

33

There is a socket.on('disconnect', function () { ... });. So you can just do

socket.on('disconnect', function () {
    setTimeout(function () {
         //do something
    }, 10000);
});

EDIT 1:

I get it now. So maybe you should do something like this:

Client:

//right after connection
socket.emit('register', localstorage.getItem('gameUniqueId'));

//somewhere, when game starts
var randomlyGeneratedUID = Math.random().toString(36).substring(3,16) + +new Date;
localStorage.setItem('gameUniqueId', randomlyGeneratedUID);

Server:

io.sockets.on('connection', function (socket) {
    var player = null;

    socket.on('register', function (data) {
        if (data !== null) {
            //there was something in localstorage
            if (game.Players.existsUID(data)) {
                player = game.Players.getByUID(data);
                player.disconnected = false;
            } else {
                //timed out, create new player
            }
        } else {
            //localStorage is not set, create new player
        }
    });

    socket.on('disconnect', function () {
        player.disconnected = true;
        setTimeout(function () {
            if (player.disconnected) player.delete();
        }, 10000);
    });
});
Are
  • 2,160
  • 1
  • 21
  • 31
  • Yes I already tried that. But the problem is to talk between events. The idea is to set a session id in the disconnect event. then when the connected event is triggered, check if the user has previously disconnected and cancel (or not) the timeout – m4tm4t Nov 28 '13 at 08:40
  • And now? I've changed the answer. I know that it is complicated, but I tried to simplify it (sic!). :) – Are Nov 28 '13 at 09:19