removing url params with javascript

Question

I have the following ajaxError

$(document).ajaxError(function (e, xhr, settings) {
   if ( settings.url == "/users/sign_in" ) {
        if (xhr.status == 401) {
           $('#notice_signin').html(xhr.responseText);
           $('#notice_signin').addClass("alert").addClass("alert-error");
        }
      }
});

the thing is that settings.url has different params such as locale, source, etc.. so settings.url never matches /users/sign_in but is /users/sign_in?lang=fr&source=fb

what is an easy way to strip the params?

so that settings.url will be `/users/sign_in` and not `/users/sign_in?lang=fr` — Nick Ginanto, Nov 28 '13 at 08:16

giammin · Accepted Answer · 2013-11-28T08:22:23.200

1

if you need it only to check the url you can use indexOf method

if ( settings.url.toLowerCase().indexOf("/users/sign_in")>-1)
....

Otherwise if you want to have the url withouth parameters for later usage you can use split method

var url = settings.url.split('?')[0];

edited Nov 28 '13 at 08:22

answered Nov 28 '13 at 08:16

giammin

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matk · Answer 2 · 2013-11-28T08:31:59.280

1

if (settings.url.split('?')[0] == '/users/sign_in') {
   ...
}

Note that this doesn't include error handling in case settings.url happens to be null.

As a side note, if '/users/sign_in' is the path of the current page, you might instead use window.location.pathname instead of hardcoding the value.

edited Nov 28 '13 at 08:31

answered Nov 28 '13 at 08:16

matk

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score 1 · Answer 3 · answered Nov 28 '13 at 08:18

1

Can you try using split

var urlString = '/users/sign_in?lang=fr&source=fb';
var urlArray =  urlString.split('?');
alert(urlArray[0]);
var settingsurl = urlArray[0];


if ( settings.url == "/users/sign_in" ) {
       ....
}

answered Nov 28 '13 at 08:18

Krish R

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score 0 · Answer 4 · answered Nov 28 '13 at 08:22

0

Or another option can use substring

if ( settings.url.substr(0,settings.url.indexOf("?")) == "/users/sign_in" )

answered Nov 28 '13 at 08:22

commit

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removing url params with javascript

4 Answers4