How to round a value of a String to 2 decimal places

Question

I have a String which is taken from a JSON file. I need to convert it to double or int and then round it to 2 decimal places and if its an int, round to 1 digit

for example: if it is 76424443 it should be rounded to 76.4 or if it is 7.122345936298 should be rounded to 7.12

This is what I have done so far.

int value = Integer.parseInt(value1);
value1 = String.valueOf(Math.round(value));

I also do not know if the value is double or int, should be something that works with both.

Don't understand how 76424443 should be converted to 76.4. May you explain a little more about what you want ? — , Nov 28 '13 at 22:08
@ᴋᴇʏsᴇʀ as it is 76 millions, cant I show it 76.4 m ?! — Alex, Nov 28 '13 at 22:16
@Gaëtan because it is a big unnecessary number, they normally show it like 76.4 m that means 76 millions and something... . That was what I wanted but if it is not possible, then I only need something to convert string to double and only show 2 floating points and if it has not floating points then only shows first 2 digits. like instead of 76424443 shows 76. — Alex, Nov 28 '13 at 22:20
@DannyJj Those are two separate rounding problems. You should edit your question to say 76.4M to avoid more confusion. — keyser, Nov 28 '13 at 22:25

score 4 · Accepted Answer · answered Nov 28 '13 at 22:33

Try this code :

Double value = Double.parseDouble(value1);
String value1 = "0";
if(value != null){
    if(value == (double) Math.round(value)){
        if(value/1000000000 > 1.0){
            value1 = String.format("%.1f G", value/1000000000);
        }
        else if(value/1000000 > 1.0){
            value1 = String.format("%.1f M", value/1000000);
        }
        else if(value/1000 > 1.0){
            value1 = String.format("%.1f K", value/1000);
        }
        else{
            value1 = String.format("%.1f", value);
        }
    }
    else{
        value1 = String.format("%.2f", value);
    }
}

Is it possible to add % sign if it has floating point? I tried this but did not work. `value1 = String.format("%.2f %", value);` — Alex, Nov 28 '13 at 22:59
In String.format, % is a special character. You should escape it and do `value1 = String.format("%.2f %%", value);` — , Nov 28 '13 at 23:00

score 0 · Answer 2 · edited May 23 '17 at 12:05

0

Consider using a BigDecimal. It will let you round your values to the precision you like. Have a look at this answer: Set specific precision of a BigDecimal

If you cast a decimal value to integer then you will lose the decimal part. If that is the case then why bother rounding at all ?

edited May 23 '17 at 12:05

Community

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answered Nov 28 '13 at 22:09

An SO User

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Thanks for you answer, it seems does the job, but how should I change it to work in my case. I mean what does 12 mean that the user uses in that question? – Alex Nov 28 '13 at 22:25
Have a look at the documentation. It will provide detailed info. Plus, search for tutorials. – An SO User Nov 28 '13 at 23:13

How to round a value of a String to 2 decimal places

2 Answers2