Bash expr with 0 before decimals

Question

I am summing two small decimal numbers contained in two variables:

SEEupper=`expr $SEEmedian+$SEEthre | bc`

but since the result is a number smaller than 1, like 0.XXXX, the output is: '.XXXX'. Is there any way to have an output with the '0' before the dot and the decimals?

score 1 · Accepted Answer · answered Nov 29 '13 at 18:08

1

workaround: ... | sed -e "s|^\.|0.|"

answered Nov 29 '13 at 18:08

Sergey Fedorov

2,169
1
15
26

It seems that this doesn't work for negative numbers... – Alberto Dec 16 '13 at 14:19
`... | sed -e "s|^\(-\?\)\.|\10.|"` – Sergey Fedorov Dec 16 '13 at 14:30

score 0 · Answer 2 · answered Nov 29 '13 at 18:17

0

if you can use python:

SEEupper=`python -c "print $SEEmedian +$SEEthre"`

answered Nov 29 '13 at 18:17

PasteBT

2,128
16
17

score 0 · Answer 3 · answered Nov 30 '13 at 23:57

0

Yes, with the internal bash command printf:

printf "%g" $SEEupper

answered Nov 30 '13 at 23:57

thom

2,294
12
9

Bash expr with 0 before decimals

3 Answers3