PHP implode explode first and last array value

Question

i'm still a freshman on PHP. So i have a variable called 'full name' and i was trying to explode and implode the first and the last variable value.

$fullname='Andre Filipe da Costa Ferreira';
$namepieces=explode('', $fullname);
$flname=implode('', namepieces[0], namepieces[lastvar]);
echo "Welcome".$flname;

I would appreciate if someone could help me! Thanks :D

You're missing the `$` in front of `namepieces` on line 3; otherwise - what is the issue that you're having? Do you get an error message? A blank screen? The wrong data? — andrewsi, Nov 29 '13 at 18:14
yes, please clarify with an example: what _would_ input look like, what _should_ output be — hanzo2001, Nov 29 '13 at 18:19

jacouh · Accepted Answer · 2013-11-29T18:31:39.687

2

This with name pieces separated with a space, and works with a single name piece like Andre:

<?php
$fullname = 'Andre Filipe da Costa Ferreira';
$namepieces = explode(' ', $fullname);
$n = count($namepieces);
if($n > 1) {
  $flname = implode(' ', array($namepieces[0], $namepieces[$n-1]));
} else {
  $flname = $namepieces[0];
}
echo "Welcome " . $flname;
//
?>

This gets:

Welcome Andre Ferreira

edited Nov 29 '13 at 18:31

answered Nov 29 '13 at 18:15

jacouh

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score 2 · Answer 2 · answered Nov 14 '15 at 15:42

2

Try:

$names = explode(" ", "Andre Filipe da Costa Ferreira");
printf("Welcome %s %s", current($names), end($names));

where current() gets its first element, and end() last one.

answered Nov 14 '15 at 15:42

kenorb

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M Khalid Junaid · Answer 3 · 2013-11-29T18:21:08.557

1

You need to use end($namepieces); which returns the value of the last element or FALSE for empty array.Also your are missing $ before namepieces

$flname=implode('', $namepieces[0], end($namepieces));

end()

Another example taken from php.net for getting first and last element from array

$items = array( 'one', 'two', 'three' );
$lastItem = end( $items ); // three
$current = current( $items ); // one

edited Nov 29 '13 at 18:21

answered Nov 29 '13 at 18:13

M Khalid Junaid

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@ThomWiggers for OP's problem it suits best i have shown him both ways either using index 0 or current() – M Khalid Junaid Nov 29 '13 at 18:24
**`current()` isn't a way to get index 0**: `current()` is a way to get the current element of an array when walking through it using an iterator/`next()`/`prev()`. That it happens to be index 0 at first isn't a reason to use `current()` for this. – Thom Wiggers Nov 29 '13 at 18:30
Why is it better than using `[0]`? – Thom Wiggers Nov 29 '13 at 18:40
1

@ThomWiggers because its php's built-in function – M Khalid Junaid Nov 29 '13 at 18:41
Also OP might as well use `reset()` then which guaranteed returns the first element (and resets the pointer). See also http://stackoverflow.com/questions/1921421/get-first-element-of-an-array. – Thom Wiggers Nov 29 '13 at 18:42
I gave you a `-1` since I think your "because it's a built-in function" argument is invalid when compared to a language construct. – Thom Wiggers Nov 29 '13 at 18:48
2

@ThomWiggers i don't want to mess arround with this i have others things to do – M Khalid Junaid Nov 29 '13 at 18:59

score 1 · Answer 4 · answered Nov 29 '13 at 18:16

1

<?php
$fullname = 'Andre Filipe da Costa Ferreira';
$namepieces = explode(' ', $fullname);
$flname = implode(' ', array($namepieces[0], $namepieces[count($namepieces)-1]));
echo "Welcome " . $flname;
//
?>

answered Nov 29 '13 at 18:16

Mahendra Jella

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score 0 · Answer 5 · answered Nov 29 '13 at 18:29

Its beter way I guess

<?php
$fullname = 'Andre Filipe da Costa Ferreira';
$namepieces = explode(' ', $fullname);
$n = count($namepieces);
$n > 0 ? $flname = implode(' ', array($namepieces[0], $namepieces[$n-1])) : $flname = $namepieces[0];
echo "Welcome " . $flname;
//
?>

PHP implode explode first and last array value

5 Answers5