Unsupported URL in NSURLRequest

Question

If I run this request from my terminal I can see the JSON requests as normally:

curl -XGET 192.168.0.6:8888/scripts/data/backend2/index.php/name/_all

My code for the NSURlRequest is this:

 NSURLRequest *request = [NSURLRequest requestWithURL:
                             [NSURL URLWithString:@"192.168.0.6:8888/scripts/data/backend2/index.php/name/_all"]];

    [[NSURLConnection alloc] initWithRequest:request delegate:self];

And I am getting this error:

didFailWithError
2013-11-29 22:31:08.164 Ski Greece[607:a0b] Connection failed: Error Domain=NSURLErrorDomain Code=-1002 "unsupported URL" UserInfo=0xcd042d0 {NSErrorFailingURLStringKey=192.168.0.6:8888/scripts/data/backend2/index.php/name/_all, NSErrorFailingURLKey=192.168.0.6:8888/scripts/data/backend2/index.php/name/_all, NSLocalizedDescription=unsupported URL, NSUnderlyingError=0xdbdcc70 "unsupported URL"}

How can I make the call to that URL? I cannot access the server code - I know it is just setup to return me what I need, if I call that URL?

Add "http://" and try again? Also, do you request the port that way or via the URL Request (I'm not sure myself). — David H, Nov 29 '13 at 22:47
Agreed. Without the "http://" (or other URL prefix), it is not a URL at all. — russellm, Nov 29 '13 at 22:53
make sure your server is running and then make sure the url prefiex — Saad Chaudhry, Nov 29 '13 at 23:43

score 61 · Accepted Answer · answered Nov 30 '13 at 04:57

61

Try to include appropriate url scheme to your url, e.g.

[NSURL URLWithString:@"http://www...

answered Nov 30 '13 at 04:57

Vizllx

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13

I have a URL starting with http://... and I still get the error. Anybody knows what else could cause this? – 最白目 Feb 24 '15 at 09:31
@最白目 in my case the problem was with the end of the url. I doubt you still need answer for this but it may help someone in the future :) – i.bel Jan 20 '20 at 13:31

score 27 · Answer 2 · answered Sep 26 '15 at 22:16

27

In my case I fixed it with this :

strURL = [strURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

strURL contains the string with the URL.

answered Sep 26 '15 at 22:16

Alf G

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score 11 · Answer 3 · answered May 17 '16 at 08:01

11

In my case, I visit a service running on my own mac, so my url is 127.0.0.1:8080/list

After I add a http:// scheme. It works!

Now it is http://127.0.0.1:8080/list instead of 127.0.0.1:8080/list

answered May 17 '16 at 08:01

halftrue

149
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Keshav · Answer 4 · 2016-10-12T06:26:44.170

9

I too struggled for the same error, even though the url path was correct but there was a space in it, before http, like below:

NSString *path = @" http://www.mylink/";
NSURL *url = [NSURL URLWithString:path];

so I was getting url as nil and so it was giving "unsupported URL". then by removing the space worked for me.

edited Oct 12 '16 at 06:26

answered Dec 18 '14 at 03:11

Keshav

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Thanks a lot, you saved a day – Sakthimuthiah Oct 07 '16 at 11:57
you are welcome, if its helps you guys, can you rate up for my answer? – Keshav Oct 12 '16 at 06:28

score 3 · Answer 5 · answered Jun 10 '18 at 15:00

3

same answer as Alf G but with IOS 9+

strUrl = [strUrl stringByAddingPercentEncodingWithAllowedCharacters:NSCharacterSet.URLHostAllowedCharacterSet]

answered Jun 10 '18 at 15:00

Aviv Frenkel

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score 2 · Answer 6 · answered Jun 11 '15 at 08:04

2

In my case spaces are added to my URL. I have removed spaces and run. Please make sure you have not added any spaces to your URL even when you are passing parameters. Hope it helps someone.

answered Jun 11 '15 at 08:04

Narasimha Nallamsetty

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score 2 · Answer 7 · answered Apr 20 '16 at 15:31

2

In my case, I was passing an unwrapped optional in Swift. Once I unwrapped the optional to string, the URL was accepted correctly.

answered Apr 20 '16 at 15:31

Justin Domnitz

3,217
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score 1 · Answer 8 · answered Jul 27 '16 at 19:57

1

It seems its a malformed URL or it's not a valid url at all, try to hit this url in browser, I think you will not get any result. error code=-1002 occurs when the url is unsupported.

answered Jul 27 '16 at 19:57

Sanchit Kumar Singh

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score 0 · Answer 9 · answered May 29 '15 at 18:05

Like stated before, a space in the URL can cause this but it's also possible that your string contains an unsupported character. For example, if you copy and paste a URL from a PDF, Word or other document it might contain unsupported characters. To the eye it looks fine but not the compiler.

To fix this, in your [NSURL URLWithString:@"http://blabhblabh"] method, delete the entire line of code, not just the url, and retype the link and method by hand.

score 0 · Answer 10 · answered Jun 05 '20 at 04:02

This error can happen if your URL contains a trailing newline.

I ran into this when I was appending an API key read from a text file (to keep it out of the version control system) to the end of an URL, and the file included a training whitespace.

See https://stackoverflow.com/a/4645700/12484 for code that will trim newline characters out of a string.

score 0 · Answer 11 · answered Sep 28 '20 at 11:14

0

I solved VIA below code

FinalUrl = [FinalUrl stringByAddingPercentEncodingWithAllowedCharacters:NSCharacterSet.URLQueryAllowedCharacterSet];

Thanks.

answered Sep 28 '20 at 11:14

Aaban Tariq Murtaza

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Unsupported URL in NSURLRequest

11 Answers11

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